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3 years ago

Describe the domain and range for

Mathematics

2 answers:

swat323 years ago

7 0

Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain
Domain: [-4,∞),{x | x ≥ -4}
Range: [0,∞),{y | y ≥ 0}

larisa86 [58]3 years ago

6 0

Square root functions domain have to be set greater than or equal to zero, so we can set x+4 greater than or equal to zero.
$x + 4 \geqslant 0 \\ x \geqslant - 4 \\ \\$
[-4, + infinity)

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Anyone know these questions? I need help,please.

dexar [7]

1) there were 32 bales added

2) 8 hours

3) 74 cards

4) 11 packs

5) $57

6) ummm...$3?

7) began with 12

8) $5 per candy bar

9) 44 students on each bus

10) $77 spent on baseball gear

3 0

3 years ago

Solve for X. 20 points !!!!

GarryVolchara [31]

Answer:

4) x = - 12

5) x = 4

Step-by-step explanation:

Since points T and S are mid points of sides ML and MN of triangle MLN.

Therefore, by mid point theorem,

TS is half of LN

so,

$x + 26 = \frac{1}{2} (x + 40) \\ \\ 2(x + 26) =x + 40 \\ \\ 2x + 52 = x + 40 \\ \\ 2x - x = 40 - 52 \\ \\ x = - 12$

5) In the same way x = 4 will be the correct answer in question number 5.

3 0

3 years ago

Avani wrote the linear equation y = 5 x + 4. Then, she wrote the equation of the line that is perpendicular to y = 5 x + 4 and t

Margarita [4]

Avani wrote the linear equation y = 5x + 4. Then, she wrote the equation of the line that is perpendicular to y = 5x+ 4 and that passes through (15,–2). If her new equation is in the form $y-\frac{1}{5}x+b$ , what is the value of b?

$\bf y=mx+b$

m is the slope
b is the y-intercept

The equation of a line that is perpendicular to another line always has the opposite reciprocal slope. In the original equation, the slope is 5. The opposite of 5, which refers to the sign, is -5. The reciprocal of -5 is -1/5. That means the slope of the new line is -1/5.

The perpendicular line:

Has a slope of $-\frac{1}{5}$

Passes through the point (15, -2)

To find the equation of a line that passes through a specific point, you need to use slope-intercept form.

$\bf y-y_{1} =m(x-x_{1})$

y₁ is the y-value of the point
m is the slope
x₁ is the x-value of the point

y₁ is -2, m is -1/5, and x₁ is 15.

Substitute the known values into the equation:

$y-(-2)=-\frac{1}{5}(x-15) \rightarrow y+2= -\frac{1}{5}(x-15)$

Open the parentheses and distribute:

$-\frac{1}{5}(x-15) \rightarrow -\frac{1}{5} \cdot x\ + -\frac{1}{5} \cdot -15 \rightarrow -\frac{1}{5}x +3$

The new equation will be:

$y+2=-\frac{1}{5}x+3$

Lastly, you need to move the positive 2 to the other side to keep it in y = mx + b form.

$y+2-2=-\frac{1}{5}x+3-2 \rightarrow y=-\frac{1}{5}x+1$

The equation of the perpendicular line is:

$\bf y=-\frac{1}{5}x+1$

The value of b is 1.

5 0

3 years ago

In the rational expression,

Travka [436]

Answer:

The reason why it is incorrect to cancel the 4x in the numerator with the 4x in the denominator is because 4x is not a factor of both the numerator and the denominator

Step-by-step explanation:

The denominator of the rational expression, x^2 + 4x - 12 given above is a quadratic equation. It is not factorizable. If we factorize the numerator, 4x - 8, we would have

4 (x - 2).

This means 4x is not a factor of the numerator(4x - 8) and neither is it a factor of the denominator (x^2 + 4x - 12). This is the reason why it is incorrect to cancel the 4x in the numerator with the 4x in the denominator. The factors of the denominator can only be gotten by using the general formula for solving quadratic equations

3 0

3 years ago

Which point is the solution to the following system of equations

vivado [14]

(3,2). 3^2 + 2^2 = 13 2(3)-2= 4 Works for both, hence this is the intersecting point of the two lines.

3 0

3 years ago