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3 years ago

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Melanie made money over the summer mowing lawns in her neighborhood. She worked 35 days during the course of the summer. She mad

e a total of $971.25 from her work over the summer. Approximately how much did Melanie earn each day she worked? Show your work

1 answer:

sdas [7]3 years ago

5 0

Answer:

Step-by-step explanation:

earning each day=(971.25)/35=$27.75

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Enos took out a 25-year loan for $135,000 at an APR of 6.0%, compounded monthly, and he is making monthly payments of $869.81. W

Alborosie

Present value = 135000
Monthly interest, i = 0.06/12 = 0.005
Monthly payment, A= 869.81

Future value of loan after 16 years
$F=P(1+i)^n$ [compound interest formula]
$=135000(1+.005)^{16*12}$
$=351736.652$

Future value of payments after 16 years
$\frac{A((1+i)^n-1)}{i}$
$=\frac{869.81((1+0.005)^{16*12}-1)}{0.005}$
$=279287.456$

Balance = future value of loan - future value of payments
=351736.652-279288.456
= $ 72448.20

Note: the exact monthly payment for a 25-year mortgage is
$A=\frac{P(i*(1+i)^n)}{(1+i)^n-1}$
$=\frac{135000(0.005*(1+0.005)^{25*12}}{(1+0.005)^{25*12}-1}$
$=869.806892$

Repeating the previous calculation with this "exact" monthly payment gives
Balance = 72448.197, very close to one of the choices.

So we conclude that the exact value obtained above differs from the answer choices is due to the precision (or lack of it) of the provided data.

The closest choice is therefore <span>$72,449.19</span>

6 0

2 years ago

Read 2 more answers

Get the general term for the sequence being your t3 = 11 and the t20 = 244.2

marusya05 [52]

Answer:

nth term = $t_{n} = 7.639(1.2)^{n - 1}$

Step-by-step explanation:

Let us assume that the given sequence is a G.P.

Now, if the first term of the G.P. is a and the common ratio is r, then

Third term = $t_{3} = ar^{2} = 11$ .......... (1) and

20th term = $t_{20} = ar^{19} = 244.2$ ........... (2)

Now, dividing equation (2) with equation (1) we get

$\frac{ar^{19} }{ar^{2} } = \frac{244.2}{11} = 22.2$

⇒ $r^{17} = 22.2$

⇒ r = 1.2.

Hence, from equation (1) we get

a(1.2)² = 11

⇒ a = 7.639 (Approx.)

Therefore, the general term of the sequence i.e. nth term = $t_{n} = 7.639(1.2)^{n - 1}$ (Answer)

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3 years ago

Bags of pretzels are sampled to ensure proper weight. The overall average for the samples is 9 ounces. Each sample contains 25 b

77julia77 [94]

Answer:

The value is $UCL = 10.8$

Step-by-step explanation:

From the question we are told that

The sample mean is $\= x = 9 \ ounce$

The sample size is n = 25

The standard deviation is $\sigma = 3 \ ounce$

Given that the sample size is not large enough i.e n< 30 we will make use of the student t distribution table

From the question we are told the confidence level is 99.7% , hence the level of significance is

$\alpha = (100 -99.7 ) \%$

=> $\alpha = 0.003$

Generally the degree of freedom is $df = n- 1$

=> $df = 25 - 1$

=> $df = 24$

Generally from the student t distribution table the critical value of $\frac{\alpha }{2}$ at a degree of freedom of $df = 24$ is

$t_{\frac{\alpha }{2} , 24 } = 3.0$

Generally the margin of error is mathematically represented as

$E = t_{\frac{\alpha }{2} , 24} * \frac{\sigma }{\sqrt{n} }$

=> $E = 3.0 * \frac{3 }{\sqrt{25} }$

=> $E =1.8$

Gnerally the upper control chart limit for 99.7% confidence is mathematically represented as

$UCL = \= x + E$

=> $UCL = 9 + 1.8$

=> $UCL = 10.8$

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2 years ago

PLEASE HELP, 20 POINTS

iragen [17]

Answer:

#2

Step-by-step explanation:

i just know it and ive done it before bro.

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2 years ago

If Rs.8000 earns an interest of Rs.720.Find the total that has to be paid?

V125BC [204]

Answer:

8720 Is the answer you just have to add them.

8000+720

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2 years ago

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