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kotykmax [81]
3 years ago
11

What is the length of the diagonal of a 10 cm by 15 cm rectangle?

Mathematics
1 answer:
wariber [46]3 years ago
6 0

Answer:

18.03 cm

Step-by-step explanation:

The two sides of the rectangle are the legs of a right triangle and the diagonal is the hypotenuse.  We can use the Pythagorean theorem

a^2 + b^2 = c^2

10^2 +15^2 = c^2  

100 +225 = c^2

325 = c^2

Take the square root of each side

sqrt(325) = sqrt(c^2)

18.02775638 =c

Rounding to the nearest hundredth

18.03 =c

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Use the elimination method to solve the system of equations.Choose the correct ordered pair. x+y=8 x-y=6
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Answer:

Solution (7,1)

Step-by-step explanation:

Use the elimination method

x + y=8

x - y=6

--------------Add

2x = 14

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Substitute x = 7 into x + y=8

7 + y=8

y = 8 - 7

y = 1

Solution (7,1)


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3 years ago
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juin [17]

the y intercept is the constant term on the x side

-6 * -2 which is 12

we can foil this out to see that

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so the y intercept is (0,12)

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2 years ago
Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

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2 years ago
Use the figure to find measures of the numbered angles.
Dafna1 [17]

Answer:

1 = 137

2 = 43

3 = 43

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then, 43 would be corresponding angle to 2 - making them equal

2 would be vertically opposite to 3, making them equal

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4 is vertically opposite to 1 - making them equal

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