Answer:
8.356 rounded to the nearest hundredth=8.360
Answer:
0.15866.
Step-by-step explanation:
We have been given that on average, electricians earn approximately μ= $54,000 per year in the united states. Assume that the distribution for electricians' yearly earnings is normally distributed and that the standard deviation is σ= $12,000. We are asked to find the probability that the sample mean is greater than $66,000.
First of all, we will find the z-score corresponding to 66,000 using z-score formula.




Now, we need to find the probability that z-score is greater than 1 that is
.
Upon using formula
, we will get:

Upon using normal distribution table, we will get:


Therefore, the probability that the sample mean is greater than $66,000 would be 0.15866 or approximately
.
4 4/5 you make the whole number a fraction by putting a 1 under it and the multiply like normal then make it into a mixed number<span />