1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AlladinOne [14]
3 years ago
13

The Green Goober, a wildly unpopular superhero, mixes 3 liters of yellow paint with 5 liters of blue paint to make 8 liters of s

pecial green paint for his costume.
Write an equation that relates the amounts (in liters) of yellow paint (y) and blue paint (b) needed to make the Green Goober's special green paint.
Mathematics
2 answers:
weqwewe [10]3 years ago
7 0

Answer:

Hence, the expression that relates b and y is:

y=\dfrac{3}{5}b

Step-by-step explanation:

It is given that:

The Green Goober, a wildly unpopular superhero, mixes 3 liters of yellow paint with 5 liters of blue paint to make 8 liters of special green paint for his costume.

i.e. the proportion of yellow paint used = \dfrac{3}{8}

and proportion of blue paint used =  \dfrac{5}{8}.

Let 'x' be the total mixture formed.

The amount of yellow paint(y)= \dfrac{3}{8}\times x

i.e. x=\dfrac{8}{3}y

and amount of blue paint(b)= \dfrac{5}{8}\times x

i.e. x=\dfrac{8}{5}b.

Hence we can equate x from both the equation to obtain:

\dfrac{8}{3}y=\dfrac{8}{5}b\\\\\dfrac{1}{3}y=\dfrac{1}{5}b\\\\\\5y=3b\\\\\\y=\dfrac{3}{5}b

Hence, equation that relates the amounts (in liters) of yellow paint (y) and blue paint (b) needed to make the Green Goober's special green paint is:

y=\dfrac{3}{5}b

Degger [83]3 years ago
5 0

Let

y------> the amounts (in liters) of yellow paint

b-----> the amounts (in liters) of blue paint

we know that

\frac{y}{b}=\frac{3}{5}

so

y=\frac{3}{5}b

therefore

<u>the answer is</u>

y=\frac{3}{5}b

You might be interested in
PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%
Yanka [14]

Answer:

x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}

Second equation:

\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}

Third equation:

\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}

Now we use this value for "x" back in equation 1 to solve for "y":

1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}

And finally we solve for the third unknown "z":

\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12

8 0
2 years ago
Does the following equation determine y to be a function of x? y square=x+3
Phantasy [73]

Answer:

∴ y² = x + 3 is not a function

Step-by-step explanation:

* Lets explain how to solve the problem

- The definition of the function is every input (x) has only one

  output (y)

- Ex:

# y = x + 1 where x ∈ R , is a function because every x has only

  one value of y

# y² = x where x ∈ R , is not a function because y = ±√x, then one

  x has two values of y

* Lets solve the problem

∵ y² = x + 3

- Find y by taking √ for both sides

∴ y = ± √(x + 3)

- That means y = √(x + 3)  and y = - √(x + 3)

∵ (x + 3) must be greater than or equal zero because there is no

  square root for negative number

∴ x + 3 ≥ 0 ⇒ subtract 3 from both sides

∴ x ≥ -3

∴ x must be any number greater than or equal -3

- Let x = 0

∴ y = √(0 + 3) = √3 and y = - √(0 + 3) = -√3

∴ x = 0 has two values of y ⇒ y = √3 and y = -√3

- Any value of x greater than or equal 3 will have two values of y

∴ y² = x + 3 is not a function

5 0
3 years ago
Whats the answer to this???
Leno4ka [110]
Measure angle EFG = 15 degrees
Measure angle GFH = 15 degrees
8 0
2 years ago
A=B+Bcd solve for c please help
lilavasa [31]
Solve for C:
c= A - B
   _______
       bd

6 0
2 years ago
Round to the nearest hundredth.<br><br> I need to be walked through the steps :)
Mamont248 [21]
It's 45 because they are congruent. If the vertex is in the center of a circle then the angle and the arc are congruent
6 0
3 years ago
Read 2 more answers
Other questions:
  • Incoming students at a school are assigned six-digit ID numbers. The first digit is chosen at random from the digits 0 through 3
    5·2 answers
  • Byron earns $11.00 per hour. How many hours will Byron have to work to earn $143.00?
    8·2 answers
  • The larger number is 18 more than twice the smaller. If the sum of the two numbers is 93, find both numbers
    10·1 answer
  • Write an equation of the line that passes through the point(-6,-9) with slope -5
    12·1 answer
  • 47/8,5.852,5 17/20,4.71 What is this least to greatest.​
    7·1 answer
  • Write the equation of the circle in standard form: Center (7,0) R=1
    13·1 answer
  • What is the interest rate?<br><br>A) 1<br><br>B) 2<br><br>C) 4<br><br>D) 300​
    13·2 answers
  • 1/3(x - 10) = - 4<br><br> x = ?
    11·2 answers
  • Based only on the information given in the diagram, it is guaranteed that ДАВС дXYZ. A. True B. False​
    6·1 answer
  • GIVING BRAINLIEST!!
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!