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Marina CMI [18]
3 years ago
10

Identify the area of a regular hexagon with side length 14 in. rounded to the nearest tenth.

Mathematics
2 answers:
kirill115 [55]3 years ago
5 0

Answer:

whats the answer bruh

Step-by-step explanation:

kakasveta [241]3 years ago
4 0
\bf \textit{area of a regular polygon}\\\\
A=\cfrac{1}{4}ns^2\ cot\left( \frac{180}{n} \right)\qquad 
\begin{cases}
s=\textit{length of a side}\\
n=\textit{number of sides}\\
\frac{180}{n}=\textit{angle in degrees}\\
----------\\
s=14\\
n=6\leftarrow hexagon
\end{cases}
\\\\\\
A=\cfrac{1}{4}\cdot 6\cdot 14^2\cdot cot\left( \frac{180}{6} \right)

make sure your calculator is in Degree mode
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The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time
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A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

1\leq t\geq \sqrt{2}

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

h =20-5t^{2}-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height h = 15m  

Put height value in equation 1

15 =20-5t^{2}

5t^{2} =20-15

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t^{2} =1

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We know that the time is always positive, therefore t=1

when the stuntman is 10m above the ground.

height h = 10m  

Put height value in equation 1

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5t^{2} =20-10

5t^{2} =10

t^{2} =\frac{10}{5}

t^{2} =2

t=\pm\sqrt{2}

t=\sqrt{2}

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