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NISA [10]
3 years ago
14

Alex's batting average is 0.346 What is his batting average rounded to the nearest hundredth?

Mathematics
1 answer:
adell [148]3 years ago
4 0
0.35 because the hundredth is the second decimal point over and 6 means you round up
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Use natural logarithms to solve the equation. Round to the nearest thousandth. 6e4x - 2 = 3
frosja888 [35]
6 · e^(4x - 2) = 3
     e^(4x - 2) = .5
 ln e^(4x - 2) = ln (.5)
          4x - 2 = ln (.5)
               4x  = ln (.5) + 2
                 x  = (ln (.5) + 2)/4
                 x = 0.3267
                 x ≈ 0.327

Answer: B

6 0
3 years ago
X - (7) = 13 help please
Bond [772]

Answer:

x=20

Step-by-step explanation:

inverse operation

add 7 to both sides

x=20

7 0
3 years ago
Read 2 more answers
Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. HELP ASAP!!
forsale [732]

1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}

Step-by-step explanation:

The given equation is 4x^{2}-8x-1

Let a be the coefficient of x^{2}

Let b be the coefficient of x

Let c be the constant.

Then the roots α,β for the equation ax^{2}+bx+c are \dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}

So,α=\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}

β=\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}.

So the roots are 1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}

5 0
3 years ago
-<br> f(x) = x^2– 4x – 9<br> g(x) = -3x – 5<br><br> Find: f(g(x))
VikaD [51]

it would beanummberjdjdhxndns

8 0
3 years ago
What are the answers to the last two questions?
irga5000 [103]

Answer:

(-1)(x+3)(x-2)

Step-by-step explanation:

<u>Factoring</u>

We are given a trinomial:

-x^2-x+6

The following steps are done to factor the trinomial.

1. Confirm there are no common factors: No common factors (given)

2. Factor out -1:

Multiply all the terms by -1 and take -1 out:

\boxed{(-1)(x^2+x-6)}

3. Factor

x^2+x-6 = (x+p)(x+q)

We have to find two numbers p and q whose product is -6 and the sum is 1. Those numbers are 3 and -2 (in any order):

Factoring:

x^2+x-6 = (x+3)(x-2)

The final factoring is:

\boxed{(-1)(x+3)(x-2)}

3 0
3 years ago
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