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natali 33 [55]
4 years ago
5

1 over the square root of 8 = 4^(m − 2)?

Mathematics
1 answer:
andrew11 [14]4 years ago
7 0

Answer:

5.5

Step-by-step explanation:

\frac{1}{ \sqrt{8} }  =  {4}^{(m - 2)}  \\

Squaring both sides

\frac{1}{8}  =  {4}^{2(m - 2)} \\   \frac{1}{8} =   {4}^{2}   \times  {4}^{(m - 2)}  \\  \frac{1}{8 \times  {4}^{2} }  =  {4}^{(m - 2)}  \\   \frac{1}{8 \times 16}  =  {4}^{(m - 2)}  \\  \frac{1}{128}  =  {4}^{(m - 2)}  \\  log_{4}(128)  = (m - 2) \\  \frac{7}{2}  = m - 2 \\ m =  \frac{11}{2}  = 5.5

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4 years ago
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