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3 years ago

I need help on all of them pleaseeee

Mathematics

1 answer:

dmitriy555 [2]3 years ago

5 0

Step-by-step explanation:

90÷0.018=5000

90÷0.18= 500

90÷1.8 = 50

90÷18 =5

90÷180 =0.5

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Marvin collects trading cards.He stores them in boxes that hold 235 cards each.If Marvin has 4 boxes full of cards, how many car

Taya2010 [7]

235 * 4 = 940 your answer is A

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3 years ago

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Kaley cuts half of a loaf of bread into 4 equal parts. What fraction of the whole loaf does each of the 4 parts represent?

morpeh [17]

Answer:

The answer is 1/4

Step-by-step explanation:

When you split something into fourths, you each get 1/4 of it.

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Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

2 years ago

Describe a sequence of reflections, rotations, and translations that shows that quadrilateral ABCD is congruent to quadrilateral

rusak2 [61]

Answer:

Rotate it counterclockwise then reflect it across the Y-axis

hope this helped :)

Step-by-step explanation:

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3 years ago

A food processor packages orange juice in small jars. The weights of the filled jars are approximately normally distributed with

vovikov84 [41]

Answer:

6.68 %.

Step-by-step explanation:

The standardised z-score = ( 10.95 - 10.5) / 0.3

= 1.5.

Looking up the Normal Distribution tables ( area to the left) 1.5 corresponds to 0.93319 so for a weight above 10.95 the proportion is

1 - 0.93319 = 0.06681

= 6.68%.

4 0

3 years ago

I need help on all of them pleaseeee​

I need help on all of them pleaseeee