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saveliy_v [14]
3 years ago
7

ILL GIVE BRAINLIEST AND CRAZY POINTS JUST HELP!!!

Mathematics
1 answer:
kvasek [131]3 years ago
7 0

Charter Bus:

1.

350 ( distance) / 50 ( rate)  = 7 (time in hours).

Conclusion - Will take the charter bus 7 hours to drive from Norfolk to New York.

2.

12  - 6  = 6 A.M  ( counting for time left in this half of the day)

7 - 6 = 1 hour left ( which will be then 1 P.M )

Conclusion- Will arrive in New York City at 1 P.M.

Personal Vehicle:

3.

1 hour : 70 miles, 2 hours : 140 miles, 3 hours : 210 miles, 4 hours : 280 miles,     5 hours : 350 miles.

Conclusion: It will take 5 hours to get to New York City from Norfolk.

4.

12 A.M - 7:30 A.M = 4:30 A.M

5 - 4.5 = 0.5 hours left ( which will be then 12:30 P.M )

Conclusion- Will arrive in New York City at 12:30 P.M.

Meet Up:

5. By looking at the rates/ratios of both vehicles and finding out the time it would take with both vehciles also I figured out that Dakota's parents will arrive first.

I didn't include a graph, I thought that you could do that with the rates of both vehicles.

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Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

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\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

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3 years ago
X-3/2=x+8/6 solve the proportion
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Answer:

x = 17/2

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6x - 18 = 2x+16

Subtract 2x from each side

6x-2x-18 = 2x-2x+16

4x-18 = 16

Add 18 to each side

4x-18+18 = 16+18

4x = 34

Divide each side by 4

4x/4 = 34/4

x = 17/2

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