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3 years ago

What are the perimeter and area of a rectangle with a length of 20 in and a width of 15 in

Mathematics

2 answers:

eimsori [14]3 years ago

8 0

Answer:

Perimeter = (20*2) + (15*2) = 70 in

Area = 15 * 20 = 300 in²

Step-by-step explanation:

Brilliant_brown [7]3 years ago

5 0

Perimeter is 2 times the length plus 2 times the width.

Area is length times width.

Perimeter = (2 x 20) + (2 x 15) = 40 + 30 = 70 inches.

Area = 20 x 15 = 300 square inches.

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What is the median of the following data set ? {3,4,2,8,5}

Varvara68 [4.7K]

4

Explanation:

3, 4, 2, 8, 5

arrange in ascending order

2, 3, 4, 5, 8

Identify the integer at the middle

median: 4

6 0

2 years ago

On the grid draw the graph of y = 3x + 2 for values of x + 2 for values of x from -2 to 2

sladkih [1.3K]

Answer:

The required graph is shown below.

Step-by-step explanation:

Consider the provided equation $y=3x+2$

We need to draw the graph of the equation.

Put x=0 in the above equation.

$y=3(0)+2$

$y=2$

The coordinate is (0,2).

Put y=0 in the given equation.

$0=3x+2$

$-2=3x$

$x=\frac{-2}{3}$

The coordinate is ( $\frac{-2}{3}$ ,0).

Now draw the graph by using the above coordinates.

The required graph is shown below.

6 0

3 years ago

One person can do a certain job in 20 minutes and another person can do the same job in twenty eight minutes. how many minutes w

Mamont248 [21]

I'm terrible at math, so I'm sorry if I'm totally wrong, but I'm assuming you just take the average:

20+28=48m
48/2=24m

On average, it may take them 24m if they work together.

8 0

3 years ago

A curious patterns occurs in a group of people who all shake hands with one another. It turns out that you can predict the numbe

ycow [4]

Missing part of the question

Determine the number of handshakes, i, that will occur for each number of people, n, in a particular room. (people)

Answer:

$S_n = \frac{n}{2}(n - 1)$

Step-by-step explanation:

Given

For 5 people

$\begin{array}{cc}{People} & {Handshakes} & {5} & {4} & {4} & {3} & {3} & {2} & {2} & {1} & {1} & {0} &{Total} & {10} \ \end{array}$

Using the given instance of 5 people, the number of handshakes can be represented as:

$(n - 1) + (n - 2) + (n - 3) + ........ + 3 + 2 + 1 + 0$

The above sequence is an arithmetic sequence and the total number of handshakes is the sum of n terms of the sequence.

$S_n = \frac{n}{2}{(T_1 + T_n})$

Where

$T_1 = n - 1$ --- The first term

$T_n = 0$ --- The last term

So:

$S_n = \frac{n}{2}(n - 1 + 0)$

$S_n = \frac{n}{2}(n - 1)$

7 0

2 years ago

Michmoo Computer Company sells computers and computer parts by mail. The company assures its customers that products are mailed

Anastaziya [24]

Answer: (60.858, 69.142)

Step-by-step explanation:

The formula to find the confidence interval for mean :

$\overline{x}\pm z_c\dfrac{\sigma}{\sqrt{n}}$ , where $\overline{x}$ is the sample mean , $\sigma$ is the population standard deviation , n is the sample size and $z_c$ is the two-tailed test value for z.

Let x represents the time taken to mail products for all orders received at the office of this company.

As per given , we have

Confidence level : 95%

n= 62

sample mean : $\overline{x}=65$ hours

Population standard deviation : $\sigma=18$ hours

z-value for 93% confidence interval: $z_c=1.8119$ [using z-value table]

Now, 93% confidence the mean time taken to mail products for all orders received at the office of this company :-

$65\pm (1.8119)\dfrac{18}{\sqrt{62}}\\\\ 65\pm4.142\\\\=(65-4.142,\ 65+4.142)\\\\= (60.858,\ 69.142)$

Thus , 93% confidence the mean time taken to mail products for all orders received at the office of this company : (60.858, 69.142)

8 0

3 years ago