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Dovator [93]
3 years ago
9

HELP ASAP!! Identify the least common multiple of x^2 + 7x + 6 and x^2 − 3x − 4.

Mathematics
2 answers:
AnnyKZ [126]3 years ago
8 0

Answer:

The answer to your question is (x + 1)(x + 6)(x - 4)

Step-by-step explanation:

Polynomials

                         x² + 7x + 6               x² - 3x - 4

Process

1.-Factor both trinomials

                       (x + 1)(x + 6)                (x - 4)(x + 1)

2.- Select all the factors that are different

                       (x + 1)(x + 6)(x - 4)   This is the least common factor

Or we can multiply the factors

                       x³ + 3x² - 22x - 24          

vesna_86 [32]3 years ago
3 0

(x+1)(x+6)(x-4)

The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly.

Hope This Helps & Good Luck

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1/4 of a pipe is white , 1/2 part of the remaining is blue. If the remaining part is black and the length of this black part is
hram777 [196]

Answer: 14 cm

Step-by-step explanation:

First take out 1/4 of the pipe, the portion that is white.  Then, half of three quarters of the pipe is blue.  1/2 of 3/4 is 3/8.  3/8(blue) + 2/8(white) = 5/8.  Thus, 3/8 of the pipe is black.  Thus, take 5.25(The length of the black portion) and multiply it by 8/3(reciprocal of 3/8) to get 14.

Hope it helps <3

(If it does, please give brainliest, only need 1 more for rank up :) )

5 0
3 years ago
Help Please ( and leave on how you solved it ) ":(<br> view pic below
Anton [14]

Answer:

The value of x = 10.

Step-by-step explanation:

From the given triangle,

  • The value of angle M = (3x + 28)°
  • The value of angle K = (5x - 18)°
  • The value of angle L = 90°

We know that the sum of a triangle is 180°.

i.e.

K + L + M = 180°

(5x - 18)° + 90° + (3x + 28)° = 180°

5x-18+90+3x+28=180

5x+3x-18+90+28=180

8x-18+90+28=180

8x+100=180

8x=80

\frac{8x}{8}=\frac{80}{8}

x=10

Therefore, the value of x = 10

8 0
2 years ago
PLEASE HELP QUESTION IN PICTURE
Afina-wow [57]
I think it's A! definitely not C or D
8 0
2 years ago
4. The diagram at right shows the graph of 3x + 4y = 12. The shaded figure is a square, three of whose vertices are on the coord
nikklg [1K]

Remark

This is a very interesting question.  Draw a line from the origin to where the upper right vertex of the square touches the line. That line has the property that the its equation is y = x. So the "solution" to the point of intersection is the solution of the two equations.

y =  x            (1)

3x + 4y = 12 (2)

Put x in for y in equation 2

3x + 4x = 12

7x = 12

x = 12/7

x = 1.714

y = 1.714

Problem A

<em><u>x intercept</u></em>

The x intercept occurs when y = 0

3x + 4(0) = 12

3x = 12                Divide by 3

x = 12/3

x = 4

the x intercept = (4,0)

<em><u>y intercept</u></em>

The y intercept occurs when x =0

3(0) + 4y = 12

4y = 12

y = 12/4

y = 3

y intercept = (0,3)

Problem B

x and y both equal 1.714 so they are also the length of the square's side.

Problem C

See solution above. x =y is the key fact.

x = y = 1.714

5 0
3 years ago
Mohammad divide Rs 82000 into two parts such that the amounts at 5% per annum compound interest in 2 years and 3 years are equal
lara [203]

Answer:

Rs 42000 and Rs 40000

Step-by-step explanation:

Given that Rs 82000 is divided into two parts.

Let the first part be Rs x which is compounded annually at the interest of 5% per annum for 2 years.

The rate of interest = 5%=0.05

The total amount after 2 years = x(1+0.05)^{2}\cdots(i)

The other part is Rs 82000-x which is compounded annually at the interest of 5% per annum for 3 years.

The total amount after 3 years = (82000-x)(1+0.05)^{3}\cdots(ii)

As both the amounts are equal, so from equation (i) and (ii)

x(1+0.05)^{2}=(82000-x)(1+0.05)^{3} \\\\x(1.05)^{2}=82000(1.05)^{3} -x(1.05)^{3} \\\\x(1.05^2+1.05^3)=82000\times 1.05^3 \\\\x(2.260125)=94925.25 \\\\x=94925.25/2.260125 \\\\

x= 42000

And the other part = 82000-42000 = Rs 40000

Hence, he divides the money as

Rs 42000 at 5% per annum compound interest in 2 years and

Rs 40000 at 5% per annum compound interest in 3 years.

4 0
2 years ago
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