The greatest common factor: 20x^6y 40x^4y^2 10x^5y^5 is 10x^4y.
20x^6y = 10x^4y*2x^2
40x^4y^2 = 10x^4y*4y
10x^5y^5 = 10x^4y*y^4
Answer:
56 units²
Step-by-step explanation:
Each triangle has an area that is ...
... A = 1/2bh = 1/2·7·4
There are 4 such triangles, so the total area is ...
... 4A = 4(1/2)·7·4 = 2·7·4 = 56 . . . . units²
_____
An area formula customarily used when the diagonals are pependicular to each other is that the area is half the product of their lengths.
... A = (1/2)d1·d2 = (1/2)·14·8 = 56
Answer:
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Step-by-step explanation:
whats your question
ANSWER:
The surface area of the star is 3.2700 x 
square kilometres.
EXPLANATIONS:
Diameter of the star = 1.8083 x 
Km.
Surface area of the star = 4
Where n is the radius of the star.
So that;
n = 
= 0.90415 x
n = 0.90415 x Km
Thus,
Surface area = 4 x 
= 326994889
Surface area = 3.2700 x 
Therefore, the surface area of the star is 3.2700 x square kilometres.
Answer is -2(3p+10)
hope this helps :)
