Question

Please help ASAP with this one too! Thanks!

Answer 1

$The\ point-slope\ form:y-y_1=m(x-x_1)\\\\(-2;-3)\to x_1=-2;\ y_1=-3\\m=-6\\\\subtitute\\\\y-(-3)=-6(x-(-2))\\y+3=-6(x+2)\\y+3=-6x-12\ \ \ |subtract\ 3\ from\ both\ sides\\\boxed{y=-6x-15}\to\fbox{A.}$

Answer 2

Hello,

y+3=-6(x+2)
==>y=-6x-15

Answer A