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oksian1 [2.3K]
4 years ago
14

How to solve a+5=-5a+5

Mathematics
2 answers:
Naddika [18.5K]4 years ago
8 0
Simplifying
a + 5 = -5a + 5

Reorder the terms:
5 + a = -5a + 5

Reorder the terms:
5 + a = 5 + -5a

Add '-5' to each side of the equation.
5 + -5 + a = 5 + -5 + -5a

Combine like terms: 5 + -5 = 0
0 + a = 5 + -5 + -5a
a = 5 + -5 + -5a

Combine like terms: 5 + -5 = 0
a = 0 + -5a
a = -5a

Solving
a = -5a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '5a' to each side of the equation.
a + 5a = -5a + 5a

Combine like terms: a + 5a = 6a
6a = -5a + 5a

Combine like terms: -5a + 5a = 0
6a = 0

Divide each side by '6'.
a = 0

Simplifying
a = 0
allochka39001 [22]4 years ago
5 0

1 Cancel 5 on both sides.

a=-5aa=−5a

2 Subtract -5a−5a from both sides.

a+5a=0a+5a=0

3 Simplify a+5aa+5a to 6a6a.

6a=06a=0

4 Divide both sides by 66.

a=0a=0

------------------------------------------------------------------------------------------

a+5=-5a+5a+5=−5a+5

1 Let a=0a=0.

0+5=-5\times 0+50+5=−5×0+5

2 Simplify 5\times 05×0 to 00.

0+5=-0+50+5=−0+5

3 Simplify 0+50+5 to 55.

5=-0+55=−0+5

4 Simplify -0+5−0+5 to 55.

5=55=5

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The first side of a triangle is 2 inches shorter than the second side. The third side is 5 inches longer than the second side. I
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Let the length of second side be x" ,

So,
Length of first side = 2" shorter than second = ( x - 2 )"
Length of third side = 5" longer than second = ( x + 5 )"




=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=




\text{Perimeter = sum of all sides  }



Given, perimeter = 33"




= > first side + second side + third side = 33"


= > ( x - 2 ) + x + ( x + 5 ) = 33

= > x - 2 + x + x + 5 = 33

= > 3x + 3 = 33

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Hence, length of each side is

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3 years ago
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