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Anna007 [38]
3 years ago
13

Expand [a/3-b/6-1]^2

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
6 0

Answer:

Step-by-step explanation:

(x + y +z)^2 = x² + y² + z² + 2xy + 2yz + 2zx

x = a/3

y = -b/6

c = -1

[\frac{a}{3}-\frac{b}{6}-1]^{2}=(\frac{a}{3})^{2}+(\frac{-b}{6})^{2}+(-1)^{2}+2*\frac{a}{3}*\frac{-b}{6}+2*\frac{-b}{6}*(-1)+2*\frac{a}{3}*(-1)\\\\\\=\frac{a^{2}}{9}+\frac{b^{2}}{36}+1-\frac{ab}{9}+\frac{b}{3}-\frac{2a}{3}

KATRIN_1 [288]3 years ago
4 0

Answer:

(a/3

(  \frac{a}{3}  -  \frac{b}{5}  ) {}^{2}

\frac{ {a}^{2} }{9}  -  \frac{2ab}{15}  +  \frac{b {}^{2} }{25}

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Now, we will add another column with the squares of the values of "x". Like this:

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r=\frac{n\Sigma xy-\Sigma x\Sigma y}{\sqrt{(n\Sigma x^2-(\Sigma x)^2)(n\Sigma y^2-(\Sigma y)^2)}}

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\begin{gathered} \Sigma xy=\text{ sum of the column of xy} \\ \Sigma x=\text{ sum of the column x} \\ \Sigma y=\text{ sum of the column y} \\ \Sigma x^2=\text{ sum of the column x\textasciicircum2} \\ \Sigma y^2=\text{ sum of the column y\textasciicircum2} \\ n=\text{ number of rows} \end{gathered}

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