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2 years ago

Which value is equivalent to the expression 2^3 + 3^4

Mathematics

1 answer:

Nana76 [90]2 years ago

3 0

Answer:

Step-by-step explanation:

2^3=2*2*2=8

3^4=3*3*3*3=9*9=81

8+81=89

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Identify the sample as biased or unbiased and describe its type. John wanted to know about the popularity of a particular movie.

I am Lyosha [343]

Answer: unbiased; simple random sampling

Step-by-step explanation:

From the question, we are informed that John wanted to know about the popularity of a particular movie and that he surveyed 20% of the people in 5 different theaters.

This is an unbiased sample. This is because everybody at the theaters have an equal chance of being chosen by John.

Also, it's a simple random sampling. This is because a subset of the entire population is randomly selected.

5 0

3 years ago

5,000 kilograms minus 825 kilograms

Anna [14]

Wow. 4175 kilograms.

8 0

2 years ago

24% of U.S. adults say they are more likely to make purchases during a sales tax holiday. you randomly select 10 adults. find th

neonofarm [45]

Answer:

a) $p(X= 2) = 0.261$

b) P(x>2) = 0.566

c) P(2<x<5) = 0.334

Step-by-step explanation:

Given 24% of U.S. adults say they are more likely to make purchases during a sales tax holiday

Probability 0f U.S. adults say they are more likely to make purchases during a sales tax holiday (p) = 0.24

n = 10

By using Poisson distribution

mean number of make purchases during a sales tax holiday

λ = np = 10 X 0.24 = 2.4

The probability of getting exactly '2'

The probability $p(X= 2) = e^{-\alpha } \frac{\alpha^r }{r! }$

$p(X= 2) = e^{2.4 } \frac{\(2.4)^2 }{2! }$

$p(X= 2) = e^{2.4 } \frac{\(2.4)^2 }{2! }= 0.261$

b) The probability of getting more than '2'

$P(X>2) = 1- {p(x=0)+p(x=1)+p(x=2)}$

$= e^{-2.4 } \frac{(2.4)\^0 }{0! }+ e^{-2.4 } \frac{(2.4)\^1 }{1!}+e^{-2.4 } \frac{(2.4)\^2 }{2!}$

= 0.090 + 0.2177+0.261 = 0.566

P(x>2) = 0.566

c) The probability of getting between two and five

P( 2<x<5) = P(x=3)+p(x=4) = $= e^{-2.4 } \frac{(2.4)\^3 }{3! }+ e^{-2.4 } \frac{(2.4)\^4 }{4!}+$

P(2<x<5) = 0.2090 + 0.125 = 0.334

4 0

2 years ago

Graph the line with x-intercept 9 and y-intercept 7.<br>What is the slope m of this line?

DIA [1.3K]

Here u go I hope this helps

7 0

2 years ago

A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)

Maksim231197 [3]

Answer:

The 95% confidence interval is $0.0503 < p < 0.1297$

The sample proportion is $\r p = 0.09$

The critical value is $Z_{\frac{\alpha }{2} } = 1.96$

The standard error is $SE =0.020$

Step-by-step explanation:

From the question we are told that

The sample size is n = 200

The number of defective is k = 18

The null hypothesis is $H_o : p = 0.08$

The alternative hypothesis is $H_a : p > 0.08$

Generally the sample proportion is mathematically evaluated as

$\r p = \frac{18}{200}$

$\r p = 0.09$

Given that the confidence level is 95% then the level of significance is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the standard of error is mathematically represented as

$SE = \sqrt{\frac{\r p (1 - \r p)}{n} }$

substituting values

$SE = \sqrt{\frac{0.09 (1 - 0.09)}{200} }$

$SE =0.020$

The margin of error is

$E = Z_{\frac{ \alpha }{2} } * SE$

=> $E = 1.96 * 0.020$

=> $E = 0.0397$

The 95% confidence interval is mathematically represented as

$\r p - E < \mu < p < \r p + E$

=> $0.09 - 0.0397 < \mu < p < 0.09 + 0.0397$

=> $0.0503 < p < 0.1297$

7 0

2 years ago