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lina2011 [118]
2 years ago
6

Which value is equivalent to the expression 2^3 + 3^4

Mathematics
1 answer:
Nana76 [90]2 years ago
3 0

Answer:

89

Step-by-step explanation:

2^3=2*2*2=8

3^4=3*3*3*3=9*9=81

8+81=89

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Occasionally an airline will lose a bag. Suppose a small airline has found it can reasonably model the number of bags lost each
julia-pushkina [17]

Answer:

a) The probability that the airline will lose no bags next monday is 0.1108

b) The probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227

c) I would recommend taking a Poisson model with mean 4.4 instead of a Poisson model with mean 2.2

Step-by-step explanation:

The probability mass function of X, for which we denote the amount of bags lost next monday is given by this formula

P(X=k) = \frac{e^{-2.2} * {2.2}^k }{k!}

a)

P(X=0) = \frac{e^{-2.2} * {2.2}^0 }{0!} = 0.1108

The probability that the airline will lose no bags next monday is 0.1108.

b) Note that P(X \in \{0,1,2\} = P(X=0) + P(X=1) + P(X=2) . And

P(X=0)+P(X=1)+P(X=2) = e^{-2.2} * (1 + 2.2 + 2.2^2/2) = 0.6227

Therefore, the probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227.

c) If the double of flights are taken, then you at least should expect to loose a similar proportion in bags, because you will have more chances for a bag to be lost. WIth this in mind, we can correctly think that the average amount of bags that will be lost each day will double. Thus, i would double the mean of the Poisson model, in other words, i would take a Poisson model with mean 4.4, instead of 2.2.

6 0
3 years ago
An object on the moon weighs about 0.17 of what it would weigh on earth.
Ivahew [28]
The answer would be E.

All you have to do is multiply 185 by 0.17 and you get your answer, which would be E.
3 0
2 years ago
Read 2 more answers
Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be
Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of t=0.6482

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

h(t)=-16t^2 +v_{o}t+s       Eqn(1).

Where:

h(t) : is the height range as a function of time

v_{o}   : is the initial velocity

s     : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

h(t)=-16t^2 + v_{o}t + 40        Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

<u>Ben:</u>

We know that v_{o}=60ft/s

Thus Eqn. (2) becomes:

h(t)=-16t^2+60t+40        Eqn.(3)

<u>Josh:</u>

We know that v_{o}=48ft/s

Thus Eqn. (2) becomes:

h(t)=-16t^2+48t+40       Eqn. (4).

<em><u>Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at </u></em>h(t)=0<em><u>. Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one. </u></em>

Thus we have for Ben, Eqn. (3) gives:

h(t)=0-16t^2+60t+40=0

Using the quadratic expression to find the roots of the quadratic we have:

t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec

Since time can only be positive we reject the t_{2} solution and we keep that Ben's book took t=4.3276 seconds to reach the ground.

Similarly solving for Josh we obtain

t_{1}=3.6794sec\\t_{2}=-0.6794sec

Thus again we reject the negative and keep the positive solution, so Josh's book took t=3.6794 seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482

So to answer the original question:

<em>Whose textbook reaches the ground first and by how many seconds?</em>

  • Josh's textbook reached the ground first
  • Josh's textbook reached the ground first by a difference of t=0.6482

3 0
3 years ago
Consider a convex hexagon in which all pairs of opposite sides are parallel. Prove that if one pair of opposite sides have equal
hjlf

A pair of the opposite sides of a hexagon has equal length and this is proved below.

<h3>How to illustrate the hexagon?</h3>

It should be noted that a hexagon is a polygon that has six sides.

In this case, it has 6 sides.

The total angles will be:

= (n - 2) × 180

= (6 - 2) × 180

= 720°

Each angle will hence be:

= 720°/6

= 120°

Each angle are equal and this illustrates that the parallel sides are equal.

A diagram is attached to illustrate the pair of parallel sides.

Learn more about hexagon on:

brainly.com/question/1615720

#SPJ1

6 0
2 years ago
Ex plane how knowing 50 x 4 = 200 helps you find 500 x 400
Alex777 [14]

Answer:

Step-by-step explanation:

if you know 50*4=200, you must also know that 50*10=500 and that 4*100=400 so 500*400= 50*10*4*100

multiplication is comutative so

50*4*10*100=200*1,000= 200, 000

8 0
3 years ago
Read 2 more answers
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