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krok68 [10]
3 years ago
10

Verify that the divergence theorem is true for the vector field f on the region

Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0
By the divergence theorem,

\displaystyle\iint_{\partial\mathcal E}\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\iiint_{\mathcal E}\nabla\cdot\mathbf f(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz

where \partial\mathcal E is the boundary of \mathcal E. We have

\nabla\cdot\mathbf f(x,y,z)=\dfrac{\partial(4x)}{\partial x}+\dfrac{\partial(xy)}{\partial y}+\dfrac{\partial(4xz)}{\partial z}=4+x+4x=5x+4

so the flux is

\displaystyle\int_{z=0}^{z=2}\int_{y=0}^{y=2}\int_{x=0}^{x=2}(5x+4)\,\mathrm dx\,\mathrm dy\,\mathrm dz=72
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Oscar Montez’s savings account has a principal of $7,201. It earns 6% interest compounded quarterly. What is the amount of inter
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Compounded quarterly means that one quarter of the interest is added to the account each quarter one quarter of 6% is 1.5% x = 7201 (1 + .06/4)^2 ___ .06/4 is the interest per compounding , and 2 is the number of compoundings
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3 years ago
Can someone give me a simple definition for absolute value
Vitek1552 [10]
Absolute value is h<span>ow far a number is from zero.
</span>
For example |-4|=4 or |98| =98. 

6 0
3 years ago
Read 2 more answers
Can I Please Get Help I Need The Units With The Answer Too
CaHeK987 [17]

The rate of change of the the given table is: 3/4soda per dollar.

<h3>What is the Rate of Change?</h3>

Rate of change = change in total cost / change in number of sodas.

Using (24, 18) and (28, 21), we would have:

Rate of change = (21 - 18)/(28 - 24)

Rate of change = 3/4

Therefore, the rate of change is 3/4soda per dollar.

Learn more about the rate of change on:

brainly.com/question/8728504

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4 0
1 year ago
Two chemists working for a chicken fast-food company, have been producing a very popular sauce. Let’s call then Jesse and Mr. Wh
a_sh-v [17]

Answer:

Check the explanation

Step-by-step explanation:

Let \overline{x} and \overline{y} be sample means of white and Jesse denotes are two random variables.

Given that both samples are having normally distributed.

Assume \overline{x} having with mean \mu_{1} and \overline{y} having mean \mu_{2}

Also we have given the variance is constant

A)

We can test hypothesis as

H0: \mu_{1} =  \mu_{2}H1: \mu_{1} > \mu_{2}

For this problem

Test statistic is

T=\frac{\overline {x}-\overline {y}}{s\sqrt{\frac {1}{n1} +\frac{1}{n2}}}

Where

s=\sqrt{\frac{(n1-1)*s1^{2}+(n2-1)*s2^{2}}{n1+n2-2}}

We have given all information for samples

By calculations we get

s=2.41

T=2.52

Here test statistic is having t-distribution with df=(10+7-2)=15

So p-value is P(t15>2.52)=0.012

Here significance level is 0.05

Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.

We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.

3 0
3 years ago
-1.2= y/2.4 -1.7<br> Solve for y
evablogger [386]

{\huge{\boxed{\sf{Question}}

-1.2= y\div2.4 -1.7

Solve for y

{\huge{\boxed{\sf{Answer\:with\:explanation }}}

let's put our equation first

-1.2= y\div2.4 -1.7

Flip the equation

y\div2.4-1.7=-1.2

Now follow the rule of BOMDAS/PEMDAS

{\huge{\boxed{\sf{BOMDAS }}}

  • Brackets
  • Of multiplication
  • Division
  • Addition
  • Subtraction

{\huge{\boxed{\sf{PEMDAS}}}

  • Parenthesis
  • Exponents
  • Multiplication
  • Division
  • Addition
  • Subtraction

_________________________

{\huge{\boxed{\sf{Solve\:the\:equation}}}

_________________________

y\div2.4-1.7=-1.2

{\underline{simplify}}

0.416667y-1.7=-1.2

add 1.7 to both sides

0.416667y=0.5

Divide both sides by 0.416667

y=1.2

{\huge{\boxed{\sf{Answer}}}

y would equal 1.2

4 0
2 years ago
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