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krok68 [10]
3 years ago
10

Verify that the divergence theorem is true for the vector field f on the region

Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0
By the divergence theorem,

\displaystyle\iint_{\partial\mathcal E}\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\iiint_{\mathcal E}\nabla\cdot\mathbf f(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz

where \partial\mathcal E is the boundary of \mathcal E. We have

\nabla\cdot\mathbf f(x,y,z)=\dfrac{\partial(4x)}{\partial x}+\dfrac{\partial(xy)}{\partial y}+\dfrac{\partial(4xz)}{\partial z}=4+x+4x=5x+4

so the flux is

\displaystyle\int_{z=0}^{z=2}\int_{y=0}^{y=2}\int_{x=0}^{x=2}(5x+4)\,\mathrm dx\,\mathrm dy\,\mathrm dz=72
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Answer:

Step-by-step explanation:

The answer is actually

Let:

S=1+2+3+4+5+6+7+8+9+n

We know the answer to the following infinite sum:

S2=1-1+1-1+1-1+1-1+1-1+1-1+1-....= - 1/2

We can therefore solve for this sum:

S3=1-2+3-4+5-6+7-8+9-....

We add them:

S3=      1-2+3-4+5-6+7-8...

S3=       +1-2+3-4+5-6+7-8...

        ________________

2S3=    1-1+1-1+1-1+1-1+1-....

Therefore:

2S3=S2=

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