Answer:
The temperature dropped 12 degrees over 3 hours. How much did it change each hour?
Step-by-step explanation:
This question (the answer) is asking you to do 12 divided by 3. That would be 12/3 (which is what was in the original question). Also, the temperature dropped, so that would be why it is -12/3
Answer:
Step-by-step explanation:
Consider the graphs of the 
and 
.
By equating the expressions, the intersection points of the graphs can be found and in this way delimit the area that will rotate around the Y axis.
then 
o 
. Therefore the integration limits are:
and 
The inverse functions are given by:
and 
. Then
The volume of the solid of revolution is given by:
![\int\limits^{64}_ {0} \, [2\sqrt{y} - \frac{y}{4}]^{2} dy = \int\limits^{64}_ {0} \, [4y - y^{3/2} + \frac{y^{2}}{16} ]\ dy = [2y^{2} - \frac{2}{5}y^{5/2} + \frac{y^{3}}{48} ]\limits^{64}_ {0} = 546.133 u^{2}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B64%7D_%20%7B0%7D%20%5C%2C%20%5B2%5Csqrt%7By%7D%20-%20%5Cfrac%7By%7D%7B4%7D%5D%5E%7B2%7D%20%20dy%20%3D%20%5Cint%5Climits%5E%7B64%7D_%20%7B0%7D%20%5C%2C%20%5B4y%20-%20y%5E%7B3%2F2%7D%20%2B%20%5Cfrac%7By%5E%7B2%7D%7D%7B16%7D%20%5D%5C%20%20dy%20%3D%20%5B2y%5E%7B2%7D%20-%20%5Cfrac%7B2%7D%7B5%7Dy%5E%7B5%2F2%7D%20%2B%20%5Cfrac%7By%5E%7B3%7D%7D%7B48%7D%20%5D%5Climits%5E%7B64%7D_%20%7B0%7D%20%3D%20546.133%20u%5E%7B2%7D)
You start by doing 65.20 (the bill) divided by 5 (the amount of people paying)
65.20 / 5 = 13.04
Then you add 13.04 (how much each person paid towards the bill) and 2.75 (the amount of money each person left as a tip)
13.04 + 2.75 = 15.79
Each person paid $15.79
The area of the parallelogram spanned by the given vectors is equal to the magnitude of their cross product.
(i + j + k) × (-2i + 3j + k)
= -2 (i × i) - 2 (j × i) - 2 (k × i)
… + 3 (i × j) + 3 (j × j) + 3 (k × j)
… + (i × k) + (j × k) + (k × k)
= - 2 (j × i) - 2 (k × i) + 3 (i × j) + 3 (k × j) + (i × k) + (j × k)
= 2 (i × j) - 2 (k × i) + 3 (i × j) - 3 (j × k) - (k × i) + (j × k)
= 5 (i × j) - 3 (k × i) - 2 (j × k)
= 5 k - 3 j - 2 i
Then the area of the parallelogram is
||-2 i - 3 j + 5 k|| = √((-2)² + (-3)² + 5²) = √38
