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Naddik [55]
3 years ago
6

Your plant produces 100 snowmobiles per month. Direct costs are $2,000 per snowmobile. Monthly overhead is $90,000. What is the

average cost per snowmobile with overhead?
Business
1 answer:
fenix001 [56]3 years ago
7 0

Answer:

$2,900

Explanation:

If we use a cost function, it will be easy to understand. Cost function = (variable cost per unit × quantity) + fixed cost.

Here,

Direct cost per snowmobile = $2,000. It is the variable cost.

Overhead cost = $90,000. It is a fixed cost.

Total snowmobiles = 100 units

Total cost = ($2,000 × 100 snowmobiles) + $90,000

Total cost = $290,000

We know,

Average cost per snowmobile = Total cost ÷ total quantity

Average cost per snowmobile = $290,000 ÷ 100

Average cost per snowmobile = $2,900

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stiks02 [169]

Answer:

Effect on income= $0

Explanation:

<u>Because the company has excess capacity and it is a special offer that would not affect normal sales, we will not include the fixed costs.</u>

Effect on income= total sales revenue - total variable cost

Effect on income= 24*4,960 - (20 + 4)*4,960

Effect on income= $0

8 0
3 years ago
Suppose that the market demand curve for bean sprouts is given by P = 1,660 - 4Q, where P is the price and Q is total industry o
a_sh-v [17]

Answer:

In equilibrium, total output by the two firms will be option e= 300.  

Q = q_{1} + q_{2}

Q = 100 + 200

Q = 300

Explanation:

Data Given:

Market Demand Curve = P = 1660-4Q

where, P = price and Q = total industry output

Each firm's marginal cost = $60 per unit of output

So, we know that Q =  q_{1} + q_{2}

where q_{} being the individual firm output.

Solution:

P = 1660-4Q

P = 1660- 4(q_{1} + q_{2})

P = 1660 - 4q_{1} - 4q_{2}

Including the marginal cost of firm 1 and multiplying the whole equation by q_{1}

Let's suppose new equation is X

X =  1660q_{1} - 4q_{1} ^{2} - 4q_{1}q_{2} - 60q_{1}

Taking the derivative w.r.t to q_{1}, we will get:

X^{'} = 1660 - 8q_{1} - 4q_{2} - 60 = 0

Making rearrangements into the equation:

8q_{1} + q_{2} = 1660 - 60

8q_{1} + q_{2} = 1600

Dividing the whole equation by 4

2q_{1} +q_{2} = 400

Solving for q_{1}

2q_{1} = 400 - q_{2}

q_{1} = 200 - 0.5 q_{2}  

Including the marginal cost of firm 1 and multiplying the whole equation by q_{2}

P = 1660 - 4q_{1} - 4q_{2}

Let's suppose new equation is Y

Y =  1660q_{2} - 4q_{1}q_{2} -4q_{2} ^{2} - 60q_{2}

Pugging in the value of q_{1}

Y =  1660q_{2} - 4q_{2}(200 - 0.5 q_{2}) -4q_{2} ^{2} - 60q_{2}

Y =  1660q_{2} - 800q_{2} +2q_{2} ^{2} -4q_{2} ^{2} - 60q_{2}

Y =  1600q_{2} - 800q_{2} -2q_{2} ^{2}

Taking the derivative w.r.t q_{2}

Y^{'} = 1600 - 800 - 4q_{2} = 0

Solving for q_{2}

4q_{2} = 800

q_{2} = 200

q_{1} = 200 - 0.5 q_{2}

Plugging in the value of q_{2} to get the value of q_{1}

q_{1} = 200 - 0.5 (200)

q_{1} = 200 - 100

q_{1} = 100

Q = q_{1} + q_{2}

Q = 100 + 200

Q = 300

Hence, in equilibrium, total output by the two firms will be option

e= 300.

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3 years ago
gayla quickly arranged to sell riha's car to a denver public school official; the signature on the auto's title assignment appea
shepuryov [24]

Gayla arranged to sell Riha's car to a Denver Public School employee right away; Riha's name appeared to be on the car's title assignment. She sold Riha's property and relocated all of his furnishings and personal belongings to her Denver residence. She gave the Denver Art Museum his collection of artwork, which was valued at about $19,000. She donated his books to Denver's Loretto Heights College. Gayla divided up all of his belongings.

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When a business is more successful than its rivals at attracting customers and handling competition, it is said to have a(n) ___
densk [106]

Answer:

d. Marketing

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The correct answer is technology.

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