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3 years ago

Use an iterated integral to find the area of the region bounded by the graphs of the equations.

Mathematics

1 answer:

Goryan [66]3 years ago

5 0

Answer:

use photomath and it will solve ur problem

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Determine whether the following series converge or diverge

Mars2501 [29]

An alternating series $\sum\limits_n(-1)^na_n$ converges if $|(-1)^na_n|=|a_n|$ is monotonic and $a_n\to0$ as $n\to\infty$ . Here $a_n=\dfrac1{\ln(n+1)}$ .

Let $f(x)=\ln(x+1)$ . Then $f'(x)=\dfrac1{x+1}$ , which is positive for all $x>-1$ , so $\ln(x+1)$ is monotonically increasing for $x>-1$ . This would mean $\dfrac1{\ln(x+1)}$ must be a monotonically decreasing sequence over the same interval, and so must $a_n$ .

Because $a_n$ is monotonically increasing, but will still always be positive, it follows that $a_n\to0$ as $n\to\infty$ .

So, $\sum\limits_n(-1)^na_n$ converges.

5 0

3 years ago

Find the complete factorization of the expression. 48x + 56xy A) 8x(6 + 7y) B) 8x(7 + 6y) C) 8xy(6 + 7) D) 8xy(13)

mel-nik [20]

Hello there!

The expression:48x+ 56xy

We know we can't add them together since 56 is being multiplied by y. We aren't going to combine 48x and 56xy. They will remain separate terms.

We know that "C" and "D" are not the answers.

However, we can check the following expressions to see if they match the given expression.

8x(6+7y)= 8x*6= 48x 8x*7y= 56xy <=== "A" is correct

"A" is the correct answer.

I hope this helps!
~kaikers

4 0

3 years ago

Determine which trig ratio you would use to find the height of the tree.

Viktor [21]

Sin= p/h , cos= b/h , tan= p/b

3 0

3 years ago

Which term describes the polynomial 6 + 3x + 4y?

vovangra [49]

The term that describes this polynomial is Linear trinomial.

6 0

3 years ago

Read 2 more answers

If the numbers 4, 5 and 6 are each used exactly once to replace the letters in the expression A ( B − C ), what is the least pos

guapka [62]

Answer:

The least possible result is <em>-10</em>.

Step-by-step explanation:

Given the numbers 4, 5 and 6 are to be chosen one of the letters A, B or C.

First of all,

Let A = 4, B = 5 and C = 6

$A(B-C) = 4 \times (5-6) = 4 \times -1 = -4$

Let A = 4, B = 6 and C = 5

$A(B-C) = 4 \times (6-5) = 4 \times 1 = 4$

Let A = 5, B =4 and C = 6

$A(B-C) = 5 \times (4-6) = 5 \times -2 = -10$

Let A = 5, B = 6 and C = 4

$A(B-C) = 4 \times (6-4) = 4 \times 2 = 8$

Let A = 6, B = 4 and C = 5

$A(B-C) = 6 \times (4-5) = 6 \times -1 = -6$

Let A = 6, B = 5 and C = 4

$A(B-C) = 6 \times (6-5) = 6 \times 1 = 6$

Summarizing the above values in the form of a table:

$\begin{center}\begin{tabular}{ c c c c}A & B & C & A(B-C)\\ 4 & 5 & 6 & -4\\ 4 & 6 & 5 & 4\\ 5 & 4 & 6 & -10\\ 5 & 6 & 4 & 10\\ 6 & 4 & 5 & -6\\ 6 & 5 & 4 & 6\end{tabular}\end{center}$

So, the least possible result is <em>-10</em>.

3 0

3 years ago