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3 years ago

(5x+57°) = (x+15°) find x

Mathematics

1 answer:

nataly862011 [7]3 years ago

7 0

Answer:

92x

Step-by-step explanation:

I just did a quiz with this question and got it right.

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Let X1, . . . ,Xn ∈ R be independent random variables with a common CDF F0. Let Fn be their ECDF and let F be any CDF. If F = Fn

Georgia [21]

Answer:

See the proof below.

Step-by-step explanation:

For this case we need to proof that: Let $X_1, X_2, ...X_n \in R$ be independent random variables with a common CDF $F_0$ . Let $F_n$ be their ECDF and let F any CDF. If $F \neq F_n$ then $L(F)$

Proof

Let $z_a$ different values in the set { $X_1,X_2,...,X_n}$ } and we can assume that $n_j \geq 1$ represent the number of $X_i$ that are equal to $z_j$ .

We can define $p_j = F(z_j) +F(z_j-)$ and assuming the probability $\hat p_j = \frac{n_j}{n}$ .

For the case when $p_j =0$ for any $j=1,....,m$ then we have that the $L(F) =0< L(F_n)$

And for the case when all $p_j >0$ and for at least one $p_j \neq \hat p_j$ we know that $log(x) \leq x-1$ for all the possible values $x>0$ . So then we can define the following ratio like this:

$log (\frac{L(F)}{L(F_n)}) = \sum_{j=1}^m n_j log (\frac{p_j}{\hat p_j})$

$log (\frac{L(F)}{L(F_n)}) = n \sum_{j=1}^m \hat p_j log(\frac{p_j}{\hat p_j})$

$log (\frac{L(F)}{L(F_n)}) < n\sum_{j=1}^m \hat p_j (\frac{p_j}{\hat p_j} -1)$

So then we have that:

$log (\frac{L(F)}{L(F_n)}) \leq 0$

And the log for a number is 0 or negative when the number is between 0 and 1, so then on this case we can ensure that $L(F) \leq L(F_n)$

And with that we complete the proof.

8 0

3 years ago

Which of the following is the accurate APA format for writing out the bragger condition main effect result for the willingness o

Rama09 [41]

Answer:

First, the main effect for bragger condition is significant because F statistic is F(1,116) = 68.65 with p value = 0.000, which is less than 0.001

mean and standard deviation for truthful Bragger condition are 6.83 and 1.14

mean and standard deviation for untruthful Bragger condition are 5.80 and 0.82

So, it is clear that the Edward was more likeable in the Truthful Bragger condition.

Therefore, option D is answer

5 0

3 years ago

Evaluate log3^8, given log3^2 is equivalent to 0.631

elixir [45]

We will use the followin property of logarithms:

$log(a^b) = b log(a)$

So, we have

$log(3^2) = 2 log(3) = 0.631$

If you multiply both sides by 4, you get

$8log(3) = log(3^8) = 2.524$

7 0

3 years ago

Suppose 2 eggs with bacon cost 2.70 . One egg with bacon costs 1.80 . At thesebrates what will bacon alone cost

Leno4ka [110]

If 2 eggs with bacon cost 2.70, and 1 egg with bacon costs 1.80, that means that 1 egg costs 0.90, so when we subtract once more 0.90 we get the price of the bacon alone, which is in this case 0.90.

5 0

3 years ago

Jason consumes 1500 calories and needs to

Lubov Fominskaja [6]

Answer:

100*150=15000 calories

Step-by-step explanation:

100 times 150 is 15000 because you are multipling 2 people

I don't know if it is correct

just check and if it isn't then check some one elses work.

6 0

3 years ago