Answer:
Quadrant III
Step-by-step explanation:
Quadrant I -> (+x,+y)
Quadrant II -> (-x,+y)
Quadrant III -> (-x,-y)
Quadrant IV -> (+x,-y)
If x and y must both be less than 0, then they must both be negative. Therefore, Quadrant III is your answer.
Answer:
The answer to the expression is 8
Answer:
Step-by-step explanation:
the funny lines in the corners of the triangle mean that the angles are the same. Maybe you knew that?
The supplementary angle at the top right is just
180- 17x -23
now you have expressions for each of the 3 angles of the triangle which all add up to 180°
180= 7x + 2 + 7x +2 + 180- (17x -23)
180 = 14x +4 + 180 - 17x +23
180 = -3x +207
3x = 27
x = 9
27x^2-81x-9x+27 In this case, just in your mind multiply 27 (coefficient of x^2) by the constant value 27(the end value of the quadratic trinomial). Then find factors that give you the value -90 when you add and 729 (27*27) when you multiply.
Factorise the values
27x( x-3)-9(x-3)
Which will give you
(27x-9)(x-3)
Hello,
==>h=3*4=12
[68-12, 68+12] is the interval
Answer A
