All categories

4 years ago

Check whether the given number is a solution of the equation or

Mathematics

2 answers:

shutvik [7]4 years ago

6 0

Step-by-step explanation:

13. 3×2=6 6+2=8

2 is not the solution

14. 3×2=6 6+8=14

14 is not greater than 15 so 2 is not the solution.

15. 11×3=33 33-5=28

3 is the solution

maxonik [38]4 years ago

5 0

Answer:

13. is a solution of the equation. 14. and 15. are both inequalities.

Step-by-step explanation:

the equal sign is something you can look out for to decide if it is a solution to the equation. the > sign means 'greater than' and the ≤ means 'less than' or 'equal to'. both are not equals, therefore they are inequalities.

You might be interested in

Help me with my math please

DIA [1.3K]

Answer:

your answer would come out to be 16 square inches.

7 0

3 years ago

(-2) 3 = plz help me I need help I need help I need help I need help

Degger [83]

Answer:

-6 is your answer.

Step-by-step explanation:

(-2)(-2)(-2)= -6

5 0

3 years ago

Read 2 more answers

Howdy! Id love to have these questions answered asap! Thank you for the help!

tiny-mole [99]

Answer:

1. B.

2. B.

Step-by-step explanation:

Trigonometry

1) Coterminal angles can be found by adding or subtracting 360° (or 2\pi radians) to a given angle. If we have 120°, adding 360° gives 480°, adding again 360° gives 840°. There is no way to get -180°, so this option is not a coterminal angle to 120°

A. $Cos (-90^o)=0$ , and not undefined

B. $Sin (-90^o)=-1$ . This is correct

C. $Tan (-90^o)$ is undefined, not zero

Thus the only correct option is B.

8 0

3 years ago

Let C be the curve of intersection of the parabolic cylinder x^2 = 2y, and the surface 3z = xy. Find the exact length of C from

Maslowich

I've attached a plot of the intersection (highlighted in red) between the parabolic cylinder (orange) and the hyperbolic paraboloid (blue).

The arc length can be computed with a line integral, but first we'll need a parameterization for $C$ . This is easy enough to do. First fix any one variable. For convenience, choose $x$ .

Now, $x^2=2y\implies y=\dfrac{x^2}2$ , and $3z=xy\implies z=\dfrac{x^3}6$ . The intersection is thus parameterized by the vector-valued function

$\mathbf r(x)=\left\langle x,\dfrac{x^2}2,\dfrac{x^3}6\right\rangle$

where $0\le x\le 4$ . The arc length is computed with the integral

$\displaystyle\int_C\mathrm dS=\int_0^4\|\mathbf r'(x)\|\,\mathrm dx=\int_0^4\sqrt{x^2+\dfrac{x^4}4+\dfrac{x^6}{36}}\,\mathrm dx$

Some rewriting:

$\sqrt{x^2+\dfrac{x^4}4+\dfrac{x^6}{36}}=\sqrt{\dfrac{x^2}{36}}\sqrt{x^4+9x^2+36}=\dfrac x6\sqrt{x^4+9x^2+36}$

Complete the square to get

$x^4+9x^2+36=\left(x^2+\dfrac92\right)^2+\dfrac{63}4$

So in the integral, you can substitute $y=x^2+\dfrac92$ to get

$\displaystyle\frac16\int_0^4x\sqrt{\left(x^2+\frac92\right)^2+\frac{63}4}\,\mathrm dx=\frac1{12}\int_{9/2}^{41/2}\sqrt{y^2+\frac{63}4}\,\mathrm dy$

Next substitute $y=\dfrac{\sqrt{63}}2\tan z$ , so that the integral becomes

$\displaystyle\frac1{12}\int_{9/2}^{41/2}\sqrt{y^2+\frac{63}4}\,\mathrm dy=\frac{21}{16}\int_{\arctan(3/\sqrt7)}^{\arctan(41/(3\sqrt7))}\sec^3z\,\mathrm dz$

This is a fairly standard integral (it even has its own Wiki page, if you're not familiar with the derivation):

$\displaystyle\int\sec^3z\,\mathrm dz=\frac12\sec z\tan z+\frac12\ln|\sec x+\tan x|+C$

So the arc length is

$\displaystyle\frac{21}{32}\left(\sec z\tan z+\ln|\sec x+\tan x|\right)\bigg|_{z=\arctan(3/\sqrt7)}^{z=\arctan(41/(3\sqrt7))}=\frac{21}{32}\ln\left(\frac{41+4\sqrt{109}}{21}\right)+\frac{41\sqrt{109}}{24}-\frac98$

4 0

4 years ago

3m+4=-11 helpies?? Ill give brainly btwww

MAXImum [283]

Answer:

m=-5

Step-by-step explanation:

3 0

4 years ago