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3 years ago

How many five-digit integers (integers from 10,000 through 99,999) are divisible by 5?

1 answer:

7 0

Okay to solve this problem you would simply do this solution. It took me a minute, haven't had to do integers in a while. :D

From 10,000 to 99,999 the numbers divisible by 5 ends in 0 or 5.
The first (most significant) digit can be any of nine from 1 to 9.
The 2nd digit can be any of 10.
The 3rd digit can be any of 10.
The 4th digit can be any of 10.
The 5th digit can be either of 2.

<span>That's 9(10)(10)(10)2=18,000
</span>
I hope this helps.

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ahrayia [7]

Answer:

The dogs path is shorter to the water bowl

Step-by-step explanation:

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3 years ago

Kaiden deposited $6200 into a savings account for which interest is compounded weekly at a rate of 2.77%.

scoray [572]

A=p(1+i/m)^mn
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3 years ago

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svp [43]

1/25

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2 years ago

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anzhelika [568]

The answer is A because you need to find the unit rate of each cost
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3 years ago

Graph the image of this figure after a dilation with a scale factor of 1/2 centered at the point (−3, 0).

lyudmila [28]

The vertices of the image of dilation are (4, 2), (-1, 2) and (3, 4)

<h3>How to graph the dilated image?</h3>

The given parameters are:

Center, (a, b) = (-3, 0)

Scale factor, k = 1/2

The vertices of the figure are

(5,4), (-5, 4) and (3,8)

The rule of dilation is represented as:

(x, y) ⇒ (k(x -a), k(y -b))

So, we have:

Point (5,4)

(x, y) ⇒ (1/2(5 + 3), 1/2(4 -0))

(x, y) ⇒ (4, 2)

Point (-5,4)

(x, y) ⇒ (1/2(-5 + 3), 1/2(4 -0))

(x, y) ⇒ (-1, 2)

Point (3,8)

(x, y) ⇒ (1/2(3 + 3), 1/2(8 -0))

(x, y) ⇒ (3, 4)

So, the vertices of the image of dilation are (4, 2), (-1, 2) and (3, 4)

See attachment for the image