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marshall27 [118]
3 years ago
9

Please answer thank you only if its for sure

Mathematics
2 answers:
kenny6666 [7]3 years ago
5 0
The answer is -2.00 I think!
Serggg [28]3 years ago
3 0
A. For sure. Hope you have an amazing day.
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The length of a rectangle is three more than twice the width. The perimeter is 96. What are the dimensions? ​
SIZIF [17.4K]

Answer:

Width =15

Length =33

Step-by-step explanation:

Take width as x

And length as 2x+3

Perimeter as 96

Formula of the perimeter of a rectangle is 2l+2w

X+×+2×+3+2×+3=96

6x+6=96

6x=96-6

6×=90

X=15

Width =x and x =15 so width =15 while length =33

7 0
4 years ago
Prove-: sin5A = 5cos^4 A sinA - 10cos^2 A sin^3 A + sin^5 A
jeyben [28]
A=x\\\\sin5x=5cos^4xsinx-10cos^2xsin^3x+sin^5x\\\\L=sin(3x+2x)=sin3xcos2x+sin2xcos3x=(*)\\-------------------------------\\sin3x=sin(2x+x)=sin2xcosx+sinxcos2x\\=2sinxcosxcosx+sinx(cos^2x-sin^2x)\\=2sinxcos^2x+sinxcos^2x-sin^3x=3sinxcos^2x-sin^3x\\-------------------------------

sin3xcos2x=(3sinxcos^2x-sin^3x)(cos^2x-sin^2x)\\=3sinxcos^4x-3sin^3xcos^2x-sin^3xcos^2x+sin^5x\\=3sinxcos^4x-4sin^3xcos^2x+sin^5x\\-------------------------------

cos3x=cos(2x+x)=cos2xcosx-sin2xsinx\\=cosx(cos^2x-sin^2x)-2sinxcosxsinx\\=cos^3x-sin^2xcosx-2sin^2xcosx=cos^3x-3sin^2xcosx\\-------------------------------

sin2xcos3x=2sinxcosx(cos^3x-3sin^2xcosx)\\=2sinxcos^4x-6sin^3xcos^2x\\-------------------------------


(*)=3sinxcos^4x-4sin^3xcos^2x+sin^5x+2sinxcos^4x-6sin^3xcos^2x\\\\=5sinxcos^4x-10sin^3xcos^2x+sin^5x=R

=======================================\\\\sin(\alpha+\beta)=sin\alpha cos\beta+sin\beta cos\alpha\\\\cos(\alpha+\beta)=cos\alpha cos\beta-sin\alpha sin\beta\\\\sin2\alpha=2sin\alpha cos\alpha\\\\cos\alpha=cos^2\alpha-sin^2\alpha
5 0
3 years ago
Two identical circles of radius r are inscribed in a rectangle. . a)Find the area of the rectangle as a function of r.. b)Expres
drek231 [11]
The two circles are equally inscribe inside a rectangle which means that its length is equals to the diameter of a circle and the width is two tines the diameter of a circle. 

A. The area of the rectangle using the R. is Area = 2R*4R
B. The perimeter is express as Perimeter = 2(2R*4R)
5 0
3 years ago
Read 2 more answers
Apply the distributive property to create an equivalent expression.
Amanda [17]

The distributive property: a(b + c) = ab + ac


(-7c + 8d)0.6 = (-7c)(0.6) + (8d)(0.6) = -4.2c + 4.8d

7 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Chuge%5Csf%5Cunderline%7BQuestion%7D" id="TexFormula1" title="\huge\sf\underline{Question}"
vekshin1

{\qquad\quad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

\qquad \sf  \dashrightarrow \:  {x}^{2}  +  \cfrac{1}{ {x}^{2} }  = 34

[ add 2 on both sides ]

\qquad \sf  \dashrightarrow \:  {x}^{2}  +  \cfrac{1}{ {x}^{2} } + 2  = 34 + 2

[ form identity : a² + b² + 2ab ]

\qquad \sf  \dashrightarrow \:  {(x)}^{2}  +  { \bigg(\cfrac{1}{ {x}^{} } \bigg) }^{2}  + 2 \sdot(x)  \sdot  \bigg(\cfrac{1}{x} \bigg)  = 36

[ a² + b² + 2ab = (a + b)² ]

\qquad \sf  \dashrightarrow \: {\bigg (x  +  \cfrac{1}{x}  \bigg) }^{2}  = 36

\qquad \sf  \dashrightarrow \: {\bigg (x  +  \cfrac{1}{x}  \bigg) }^{}  =  \sqrt{ 36}

\qquad \sf  \dashrightarrow \: x  +  \cfrac{1}{x}    =   \pm 6

so, the value of required expression is 6

[usually positive value is considered, but if asked the value can be either positive or negative]

8 0
2 years ago
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