3 years ago

3x + 7y = 22 12x + 28y = 88

2 answers:

5 0

-12(3x + 7y) = 22
3(12x + 28y) = 88

-36x -84y = -264
36x + 84 y = 264

0 = 0

Uf let me see I’m not sure at all, is not right let me check

ioda3 years ago

4 0

Answer:

Infinitely many solutions.

Step-by-step explanation:

3x+7y=22

12x+28y=88

--------------------

simplify 12x+28y=88 into 3x+7y=22

You might be interested in

2.96 as a mixed number or fraction in simplest form

USPshnik [31]

Answer:

2.96 = 2 96/100 = 2 24/25

7 0

3 years ago

Read 2 more answers

B) <br>(-32)+(+17)+(+32)

mart [117]

It’s 17

have a wonderful day

3 0

3 years ago

Read 2 more answers

Nelson Middle School raised $19,950 on ticket sales for its carnival fundraiser last year at $15 per ticket. If the school sells

Nina [5.8K]

Answer:

C 30600 dollars hope it helps

8 0

3 years ago

Read 2 more answers

Graph f(x) = x2 + 2x - 3, label the function’s x-intercepts, y-intercept and vertex with their coordinates. Also draw in and lab

Semenov [28]

<h2>Answer with explanation:</h2>

The given function : $f(x)=x^2+2x-3$

Using completing the squares, we have

$f(x)=x^2+2x+1-1-3$ [∵ $(x+1)^2=x^2+2x+1$ ]

$f(x)=(x+1)^2-4$ (1)

Comparing (1) to the standard vertex form $f(x)=(x-h)^2+k$ , the vertex of function is at (h,k)=(-1,-4)

For x-intercept, put f(x)=0 in (1), we get

$0=(x+1)^2-4\\\\\Rightarrow\ (x+1)^2=4$

Square root on both sides, we get

$x+1=\pm2\\\\x+1=-2\ or\ \ x+1=2\\\\=x=-3\ \ or\ x=1$

∴ x intercepts : x= (-3,0) and (1,0)

For y-intercept put x=0 in (1), we get

$f(1)=(1)^2-4=1-4=-3$

∴ y intercept : (0,-3)

Axis of symmetry : $\dfrac{-b}{2a}$

In $f(x)=x^2+2x-3$ , a=1 and b=2

Axis of symmetry= $\dfrac{-2}{2(1)}=-1$

5 0

3 years ago

How to do this here

pogonyaev

Answer:

Step-by-step explanation:

6 0

3 years ago