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vovikov84 [41]
3 years ago
12

I NEED HELP!! ASAP PLEASE!!!

Mathematics
1 answer:
mariarad [96]3 years ago
5 0

Answer:

D

Step-by-step explanation:

a:angles given do not necessarily prove that ADP and BCP is 30 they can be different

c:angles given are not in triangles

b:with regards to the square I don't think you can really prove the statement

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Ian puts 300.00 into an account to use for school expenses the account earns 6%interest compounded annually how much will be in
romanna [79]

This problem is about componded interest. The formula for compounded interest is:

\begin{gathered} \text{Amount}=\text{Initial}\cdot(1+r)^t \\ \text{Where,} \\ \text{Amount is the total acumulative at time t.} \\ \text{Initial is the initial amount, at t=0} \\ r\text{ is the interest in decimal number.} \\ t\text{ is the time accordingly the interest, in this case is in years.} \end{gathered}

In this case, Initial = 300, r = 0.06 and t=10 so the total amount in the account after 10 years is:

\begin{gathered} \text{Amount}=300\cdot(1+0.06)^{10} \\ \text{Amount}=300\cdot1.06^{10} \\ \text{Amount}=300\cdot1.79085 \\ \text{Amount}=537.255 \end{gathered}

The amount after 10 years is 573.26.

4 0
11 months ago
Which sequences of transformations will map circle<br><br> M onto circle N?
sergiy2304 [10]

Answer:

1: Reflect M across the x-axis

2: Dilate about the center by 3/2

Step-by-step explanation:

Given

See attachment for M and N

Required

Which maps M to N

The coordinates of the radius of the circles are:

M = (5,5)

N = (5,-5)

And the radius of circles are:

r_M=2

r_N=3

The first transformation from M to M' is:

- Reflect across the x-axis

The rule is:

(x,y) \to (x,-y)

M(5,5) \to M'(5,-5)

<em>At this point, M' and N now have the same center but different radius.</em>

The second transformation from M' to N is:

- Dilate about the center by dividing the radius of N by the radius of M

i.e.

k =\frac{r_N}{r_M}

k =\frac{3}{2}

<em>At this point, M has been completely mapped to N.</em>

4 0
2 years ago
ASAP PLS! What is 2k^2+3k-13=k^2+15?
shepuryov [24]

2k^2+3k-13=k^2+15

subtract k^2 -15 from each side

k^2 +3k -28=0

(k+7)(k-4)=0

k=-7  k=4

Answer: k= -7,4

8 0
3 years ago
Use &gt;,&lt;,=.<br> 0.94___0.49
uranmaximum [27]
0.94>0.49 because 0.94 is the larger number.

5 0
3 years ago
Read 2 more answers
If y varies inversely with the square of x, and y = 26 when x = 4, find y when x = 2. Question 20 options: A) 52 B) 13 C) 208
babymother [125]
I believe your answer is A.
8 0
2 years ago
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