after 4 days 88 boats will have passes under the bridge
<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
x=4.75
6×4.75=28.5
15×4.75-12=59.25
19×4.75+2=92.25
28.5+59.25+92.25=180
m<MNI= 92.25
I think this is right. I hope that it was helpful:)
The answer is 4.51 and what needs to be added to 4.5 is a .01
Subtract t the first 2 choices from the total time:
10 - 3.2 - 3.5 = 3.3
The 3rd selection needs to be 3.3 minutes long
