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3 years ago

8

Finding the area of a circle with a circumference of 53.41 inches

1 answer:

hjlf3 years ago

6 0

A≈227 would be your answer, hope this helps

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***WILL GIVE BRAINLIEST***<br> graph y= -3x +7 show picture please

CaHeK987 [17]

Answer: ok bet

Step-by-step explanation: theres a picture below and to graph it you simply start with the y coordinate, which is 7. you put 7 on the graph then go down 3 because 3 is negative, then go right one because 1 is postitive. (you get 1 from making the slope into a fraction, -3/1) also remember the formula for this is y=mx+b. its tricky but i hope this helped

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3 years ago

Is (5,15) a solution of the equation y= 3x? (plz answer asap)

sashaice [31]

Answer:

Yes

Step-by-step explanation:

15 = 3(5)

15 = 15

You plug in the point

6 0

3 years ago

I will mark brainlist please help!!

elena-14-01-66 [18.8K]

I’ve never see the truth about coks so it’s 27 inches for sure if it was all the same as2,2 743+77482=747474

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2 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

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3 years ago

Julisha poured 0.9 liter of water into an

qaws [65]

Answer:

Step-by-step explanation:

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3 years ago