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34kurt
3 years ago
11

Julisha poured 0.9 liter of water into an

Mathematics
1 answer:
qaws [65]3 years ago
8 0

Answer:

Step-by-step explanation:

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the probability tree diagram shows the probabilities that a football team will win their first two games find the probability of
nevsk [136]

Answer:1/2

Step-by-step explanation:

7 0
3 years ago
Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case. ( pls answer fast )
vagabundo [1.1K]

Answer:

95

Step-by-step explanation:

The smallest number that divided by 6, 15, and 18 leavses 5 in each case is 95

8 0
2 years ago
37. Three married couples have purchased tickets for a play. Spouses are to be seated next to each other, and the six seats are
Maurinko [17]

48

1st seat 6 possible for each 6 only 1 possible(spouse) for seat 2

3rd seat 4 possible for each 4 only 1 possible(spouse) for seat 4

5th seat 2 possible for each 2 only 1 possible(spouse) for seat 6

6 x 4 x 2 = 48

OR 3 couples possible arrangements 3 x 2 x1 = 6

each couple 2 possible 2 x 2 x 2 = 8

therefore 6 x 8 = 48

8 0
2 years ago
When a series of events takes place, each with a fixed number of possible values, the total number of possible outcomes is the _
zalisa [80]

When a series of events takes place, each with a fixed number of possible values, the total number of possible outcomes is the product of the number of values of each event. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

6 0
3 years ago
In the figure above, the vertices of square
Olin [163]

(C) 6 + 3√3

<u>Explanation:</u>

Area of the square = 3

a X a = 3

a² = 3

a = √3

Therefore, QR, RS, SP, PQ = √3

ΔBAC ≅ ΔBQR

Therefore,

\frac{BQ}{BA} = \frac{QR}{AC}

\frac{BQ}{BA} = \frac{\sqrt{3} }{BA}

In ΔBAC, BA = AC = BC because the triangle is equilateral

So,

BQ = √3

So, BQ, QR, BR = √3 (equilateral triangle)

Let AP and SC be a

So, AQ and RC will be 2a

In ΔAPQ,

(AP)² + (QP)² = (AQ)²

(a)² + (√3)² = (2a)²

a² + 3 = 4a²

3 = 3a²

a = 1

Similarly, in ΔRSC

(SC)² + (RS)² = (RC)²

(a)² + (√3)² = (2a)²

a² + 3 = 4a²

3 = 3a²

a = 1

So, AP and SC = 1

and AQ and RC = 2 X 1 = 2

Therefore, perimeter of the triangle = BQ + QA + AP + PS + SC + RC + BR

Perimeter = √3 + 2 + 1 + √3 + 1 + 2 + √3

Perimeter = 6 + 3√3

Therefore, the perimeter of the triangle is 6 + 3√3

8 0
3 years ago
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