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2 years ago

Sorry I need help on this because I don’t understand how to do this and is do 11:59 I got only a hour to do it, please help

Mathematics

1 answer:

Len [333]2 years ago

6 0

Answer:

the bottom one is 1 the second one is 46 and the top one is 500

Step-by-step explanation:

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Solve with elimination , please help.

Svetlanka [38]

This is the answer the x=3 and the y=2

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3 years ago

Solve the equation 4.8y-6.9=3.18 Explain your thinking

Alex777 [14]

4.8y - 6.9 = 3.18
4.8y= 3.18 + 6.9 (I added 6.9 to both sides)
4.8 y = 10.08 (I added 3.18 by 6.9)
y = 2.1 (I divided 4.8)

Hope this helps!!

5 0

3 years ago

Read 2 more answers

A rectangle has an area of 72 swaure units. The width of the rectangle is 9 units. The length of the rectangle is 2x + 4. What i

vichka [17]

Answer:

8 units

Step-by-step explanation:

Area of a rectangle = Width multiplied by Length

Substitute in all the known numbers into this formula to get

72 = (9) × $(2x+4)$

Solve the equation for x, to find out the length

$9(2x+4)=72$

$2x+4=72/9$

$2x+4=8$

$2x=8-4$

$2x=4$

$x=4/2$

$x=2$

Length of the rectangle = $(2x+4)$

$2(2)+4$

$4+4=8$

5 0

2 years ago

Which is the value of this expression when p=-2 and q=-1?

saul85 [17]

Answer:

D. 4

Step-by-step explanation:

$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$

8 0

2 years ago

A right triangle has side lengths 7, 24, and 25 as shown below.

Alla [95]

9514 1404 393

Answer:

tan(A) = 7/24
sin(A) = 7/25
cos(A) = 24/25

Step-by-step explanation:

The mnemonic SOH CAH TOA can help you remember the trig ratios:

Sin = Opposite/Hypotenuse

Cos = Adjacent/Hypotenuse

Tan = Opposite/Adjacent

With respect to angle A, the sides are Adjacent = 24; Opposite = 7, Hypotenuse = 25. Then the desired trig ratios are ...

tan(A) = 7/24

sin(A) = 7/25

cos(A) = 24/25

5 0

2 years ago