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3 years ago

Sorry I need help on this because I don’t understand how to do this and is do 11:59 I got only a hour to do it, please help

Mathematics

1 answer:

Len [333]3 years ago

6 0

Answer:

the bottom one is 1 the second one is 46 and the top one is 500

Step-by-step explanation:

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Write an equation for the line that passes through (2,10),(0,4)

Y_Kistochka [10]

I'm going to go right ahead and assume that we're talking about a linear equation.

The linear equation passing through the points given is y=3x+4, since it satisfies both of the points given.

8 0

3 years ago

Complete the factorization of 3x ^ 2 - 10x + 8 3x^ 2 -10x+8=(x- Box x-4)

aniked [119]

Answer:

$3x^2-10x+8=(x-x_1)(x-x_2)=(x-2)(x-\frac{4}{3})$

Step-by-step explanation:

The general form of a quadratic polynomial is given by:

$ax^2+bx+c$ (1)

You have the following polynomial:

$3x^2-10x+8$ (2)

In order to complete the factorization you can use the quadratic formula, to obtain the roost of the polynomial. The quadratic formula is given by:

$x_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ (3)

By comparing the equation (1) with the equation (2) you obtain:

a = 3

b = -10

c = 8

Then, you replace these values in the equation (3):

$x_{1,2}=\frac{-(-10)\pm \sqrt{(-10)^2-4(3)(8)}}{2(3)}\\\\x_{1,2}=\frac{10\pm2}{6}\\\\x_1=2\\\\x_2=\frac{4}{3}$

Then, the factorization of the polynomial is:

$3x^2-10x+8=(x-x_1)(x-x_2)=(x-2)(x-\frac{4}{3})$

5 0

3 years ago

Consider the differential equation: xy′(x2+7)y=cos(x)+e3xy. Put the differential equation into the form: y′+p(x)y=g(x), determin

icang [17]

Answer:

Linear and non-homogeneous.

Step-by-step explanation:

We are given that

$\frac{xy'}{(x^2+7)y}=cosx+\frac{e^{3x}}{y}$

We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).

We have also find type of differential equation.

$y'=\frac{(x^2+7)y}{x}(cosx+\frac{e^{3x}}{y}}$

$y'=\frac{(x^2+7)cosx}{x}y+\frac{(x^2+7)e^{3x}}{x}$

$y'-\frac{cosx(x^2+7)}{x}y=\frac{e^{3x}(x^2+7)}{x}$

It is linear differential equation because this equation is of the form

y'+P(x)y=g(x)

Compare it with first order first degree linear differential equation

$y'+P(x)y=g(x)$

$P(x)=-\frac{cosx (x^2+7)}{x},g(x)=\frac{e^{3x}(x^2+7)}{x}$

$\frac{dy}{dx}=\frac{(x^2+7)(ycosx+e^{3x})}{x}$

Homogeneous equation

$\frac{dy}{dx}=\frac{f(x,y)}{g(x,y)}$

Degree of f and g are same.

$f(x,y)=(x^2+7)(ycosx+e^{3x}),g(x,y)=x$

Degree of f and g are not same .

Therefore, it is non- homogeneous .

Linear and non-homogeneous.

3 0

3 years ago

What is the pattern as the exponents decrease?

qwelly [4]

Answer:

divide the previous value by 5

Step-by-step explanation:

5^2=25, 5^1=5, 25/5=5

3 0

2 years ago

Which ratio is the simplest form of ? A 2:1 B 21:14 C 3:2 D 2:3

Oxana [17]

Answer:

D 2:3

Step-by-step explanation:

The ratio can't get any smaller.

4 0

3 years ago