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Deffense [45]
3 years ago
7

What is the solution of 5y=-1x and 10y=-2x

Mathematics
1 answer:
Nana76 [90]3 years ago
4 0

the key is to get y by itself.

5y=-1x

divide each side by 5

y=-1/5x

now plug in that for y in the second equation

10(-1/5)=-2x

combine your like terms

-2=-2x

then divide each side by -2

x=1

now put them in an ordered pair.

(1,-1/5)

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Please help me with this soon much appreciated.
NeX [460]

Answer:

1 : 2

Step-by-step explanation:

this is a 30-60-90 triangle which is a special right triangle. the ratio of the sides is x: x*sqrt(3): 2x, in the order short leg: long leg: hypotenuse. so the ratio of the short leg to the hypotenuse is x:2x or 1:2

8 0
2 years ago
A box of pancake mix states that 1 1/2 cups of pancake mix and 1 cup of water are needed to make 8 pancakes. How many cups of pa
lilavasa [31]

Answer:

I think your answer is B

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Check whether the function yequalsStartFraction cosine 2 x Over x EndFraction is a solution of x y prime plus yequalsnegative 2
Jobisdone [24]

The question is:

Check whether the function:

y = [cos(2x)]/x

is a solution of

xy' + y = -2sin(2x)

with the initial condition y(π/4) = 0

Answer:

To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.

Let us do that.

y = [cos(2x)]/x

y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]

Now,

xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x

= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)

= -2sin(2x)

Which is the right hand side of the differential equation.

Hence, y is a solution to the differential equation.

6 0
3 years ago
Destiny and Guadalupe are shopping. Destiny buys 2 pairs of pants and 6 bracelets and pays $178.Guadalupe buys 3 pairs of pants
ziro4ka [17]

For the entirety of this problem, p will represent a pair of pants and b will represent a bracelet.

Step 1) Set up equations for Destiny and Guadalupe

Destiny: 178 = 2p + 6b

Guadalupe: 155 = 3p + 2b

I will be using substitution to solve this problem, but elimination can also be used.

Step 2) Solve Destiny's equation for p

178 = 2p + 6b

178 - 6b = 2p

89 - 3b = p

Step 3) Substitute the found value of p from Destiny's equation into Guadalupe's equation and solve for b

155 = 3(89 - 3b) + 2b

155 = 267 - 9b + 2b

155 = 267 - 7b

-7b = -112

b = 16

Step 4) Use the value of b found in step 3, plug that back into our equation from step 2 and solve for p

89 - 3(16) = p

89 - 48 = p

p = 41

one pair of pants = $16

one bracelet = $41

Hope this helps!! :)

4 0
3 years ago
Identify the reference angle ∅ for each given angle, 0.
frutty [35]

Answer:

When Ø = 300°, Ø = 60 degrees.

When Ø = 225°, Ø = 45 degrees.

When Ø = 480°, Ø = 60 degrees.

When Ø = -210°, Ø = 30 degrees.

Step-by-step explanation:

Reference angles are in Quadrant I (0° to 90°).

1. Find 300° (Quadrant IV) on the unit circle. Since it's in Quadrant IV, you use 360 - 300 = 60° to get your answer.

2. Find 225° (Quadrant III) on the unit circle. Since it's in Quadrant III, you use 225 - 180 = 45° to get your answer.

3. The angle 480° is not on the unit circle. To find its corresponding angle between 0° and 360°, use 480 - 360 = 120°. Then, find 120° (Quadrant II) on the unit circle. Since it's in Quadrant II, you use 180 - 120 = 60° to get your answer.

4. The angle -210° is not on the unit circle. To find its corresponding angle between 0° and 360°, use -210 + 360 = 150°. Then, find 150° (Quadrant II) on the unit circle. Since it's in Quadrant II, you use 180 - 150 = 30° to get your answer.

5 0
3 years ago
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