All categories

3 years ago

Find the value of x in each case. Give reasons to justify your solutions! XW ∥ YZ

Mathematics

1 answer:

Charra [1.4K]3 years ago

5 0

Answer:

The answer is "19".

Step-by-step explanation:

In this question, the graph file is missing which is defined in the attached file please find it.

When YZ and XW were identical,

$\angle XWY =\angle WYZ \ \ \text{(Alternate Angles)}$

$\angle XWY = 2x$

Because the angles are all 180 degrees in either a triangle:

$\to (3x - 5) + 90 + 2x = 180\\\\\to 3x - 5 + 90 + 2x = 180\\\\ \to 5 x + 85= 180 \\\\ \to 5 x = 180-85 \\\\ \to 5x = 95 \\\\ \to x= \frac{95}{5} \\\\ \to x = 19$

You might be interested in

an eagle flew 20 m above sea level.A fish was 35 m vertically below the eagle. find the position of the fish

ELEN [110]

Answer:

15m below sea level

Step-by-step explanation:

Given data

Distance of eagle from sea= 20m

Distance of fish from eagle = 35m

Required

The distance of the fish from below the sea level

= 35-20

= 15m

Hence the fish is 15m below sea level

3 0

3 years ago

If a = b and 1/x + 1/a = 1/b then x =

seraphim [82]

1/x+1/a=1/a
minus 1/a from both sides
1/x=0
false
let's try a differnt way
1/x+1/a=1/a
times both sides by xa
a+x=x
minus x from both sides
a=0
???
1/0 is undefined
this creates problems

no solution

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5C%7B%20%5Cfrac%20%7B%20%28%20%5Csqrt%20%7B%203%20%7D%20%29%20%5Ctimes%203%20%5E%20%7B%20-%20

ZanzabumX [31]

Answer:

Step-by-step explanation:

Exponent law:

$\sf \bf a^m * a^n = a^{m+n}\\\\ (a^m)^n = a^{m*n}$

$\sf a^{-m}=\dfrac{1}{a^m}$

First convert radical form to exponent form and then apply exponent law.

$\sf \sqrt{3}=3^{\frac{1}{2}}\\\\\sqrt{5}=5^{\frac{1}{2}}$

$\sf \left(\dfrac{(\sqrt{3}*3^{-2}}{(\sqrt{5})^2}\right)^{\frac{1}{2}}= \left(\dfrac{3^{\frac{1}{2}}*3^{-2}}{(5^{\frac{1}{2}})^2} \right )^{\frac{1}{2}}$

$= \left(\dfrac{3^{\frac{1}{2}-2}}{5^{\frac{1}{2}*2}}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{1-4}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{-3}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\dfrac{3^{\frac{-3}{2}*{\frac{1}{2}}}}{5^{\frac{1}{2}}}\\\\ =\dfrac{3^{{\frac{-3}{4}}}}{5^{\frac{1}{2}}}$

3 0

2 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

guajiro [1.7K]

Answer:

Step-by-step explanation:

Pythagorean formula

a²+b²=c²

in other words, sidea²+sideb²=hypotenuse

8²+15²=c²

64+225=c²

289=c²

√289=√c²

17=c

6 0

3 years ago

Lerola and her younger sister Kiara are jogging around a circular track. Lerola jogs far enough from the center of the circle th

xxTIMURxx [149]

Circumference of circular track, C = 0.5 miles = 0.5×5280 feet = 2640 feet.

We know, circumference in circle is given by :

$C = 2\pi r$

( Here, r is radius i.e distance of centre from track )

Putting values in above equation :

2 × 3.14 × r = 2640

6.28 × r = 2640

r = 420.38 feet

Therefore, distance between centre and track is 420.38 feet .

Hence, this is the required solution.

4 0

3 years ago