Four photographs

Out of the 120 students at a summer camp, 72 signed up for canoeing. There were 23 students who signed up for trekking, and 13 o

Virty [35]

Approx - 10%

72 students signed up for canoeing + the 23 students who signed up for trekking + the 13 students who signed up for both = 108 students

there are 120 students total, so you have to subtract 120 - 108 = 12

Now to find the percentage, you have to divide the number of students who didn't sign up for either, by the total

which is .1 = 10/100 = 10%

6 0

3 years ago

Read 2 more answers

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

3 years ago

A custom rectangular tabletop has a length that is twice it’s width, and the tabletop measures 76 inches on its diagonal. What a

Sunny_sXe [5.5K]

Answer:

<em>The dimensions of the tabletop: Length= 67.976... inches and Width= 33.988... inches and the perimeter will be 203.929... inches.</em>

Step-by-step explanation:

Suppose, the width of the rectangular tabletop is $x$ inch.

As the tabletop has a length that is twice it’s width, so the length will be: $2x$ inch.

The tabletop measures 76 inches on its diagonal.

<u>Formula for length of diagonal of rectangle</u>: $d=\sqrt{l^2+w^2}$

So, the equation will be..........

$76=\sqrt{(2x)^2+ x^2}\\ \\ 76=\sqrt{4x^2+x^2} \\ \\ 76=\sqrt{5x^2} \\ \\ 5x^2= 76^2= 5776\\ \\ x^2= \frac{5776}{5}=1155.2 \\ \\ x= \sqrt{1155.2} =33.988...$

Thus, the width of the tabletop is 33.988... inches and the length will be: (2×33.988...) = 67.976... inches.

The perimeter will be: 2(33.988...+ 67.976...) inches = 203.929... inches.

5 0

3 years ago

A plastic bin in the shape of a cube contains 900 marbles, each with a volume of 8 in?. If the cube has side lengths of 2 feet,

qaws [65]

900 x 8 in , 2ft in cubic inches, guessing

8 0

2 years ago

All digits in a dropdown number are different and one of the digits is the average of all the digits. it has at least two digits

sergejj [24]

The dropdown numbers is an illustration of combination

The smallest dropdown number is 1025

<h3>How to determine the smallest dropdown number?</h3>

From the question, we have the following parameters:

The dropdown number is 4-digit
The digits are different.

We start counting from 1023, 1024, 1025, 1026...........

The sum of digits in 1023 is 6, and the average is 1.5
The sum of digits in 1024 is 7, and the average is 1.75
The sum of digits in 1025 is 8, and the average is 2

The number 1025 satisfies the given conditions

Hence, the smallest dropdown number is 1025