Answer:
(f-g)(x) = x^2 - 3x + 2
Step-by-step explanation:
If f(x) = x^2+ 1 and g(x) = 3x-1
Then (f-g)(x) = (x^2+ 1 )(-(3x-1)
(f-g)(x) = x^2 + 1 - 3x + 1
(f-g)(x) = x^2 - 3x + 2
Answer: x=3
I got to the answer by doing simple math. Both sides must be even.
5x-4
5(3)-4= 15-4 = 11
x+8
3+8= 11
So x=3
Answer:
B.
Step-by-step explanation:
x = small box
(small box + 5 ounces) = large box.
B shows:
x + (x + 5) = 27
Small box + (small box + 5 ounces) = 27 ounces.
Small box + large box = 27 ounces.
————————————————————
Why A and C are incorrect.
A describes:
x + 5x = 27
Small box + 5 multiplied by small box = 27
(5 multiplied by small box is equivalent to 5 small boxes.)
Small box + 5 small boxes = 27
C describes:
x + 5 = 27
small box + 5 ounces = 27
Large box = 27
(We know that a small box + 5 ounces is a large box)
An = a1 * r^(n-1)
a1 = first term = -5
r = common ratio = -4
so ur formula is : an = -5 * -4^(n-1) <==
Answer:
C.g(x) = 5x²
Step-by-step explanation:
To find the equation for the function g(x), use the format for a quadratic equation. Without any up/down and left/right shifts, the form is y = ax².
Substituting "x" and "y" into the equation tells you if a point is on the graph.
"a" tells you the vertical stretch (greater than 1) or compression (greater than 0, less than 1).
In f(x) = x², a = 1 even though it's not written.
<u>Use the point (1, 5) on g(x) and substitute it</u> into the form for a quadratic function. Remember points are (x, y), so x = 1 and y = 5.
g(x) = ax²
y = ax² In function notation, g(x) replaces the "y". Switch it back to "y".
5 = a(1)² Substitute x = 1 and y = 5
5 = a(1) Solve the exponent first. (1)² = 1
5 = a When you multiply "a" by 1, the answer is just "a".
a = 5 Solved for "a". Put variable on left side for standard formatting.
With the quadratic form, substitute "a" into g(x).
y = ax²
g(x) = 5x²
