44
Assuming JM and LN are parallel, KMJ=MKN. MKN is part of a triangle where the other two values are defined (48 and 88). By subtracting these values from 180, we find the value of MKN is 44, which therefore is also the value of KMJ.
Answer:
35/4, or 8 3/4 as a mixed number
Step-by-step explanation:
First, change 58 1/3 into an improper fraction by multiplying the whole number and denominator, then adding the numerator. 58 x 3 equals 174, + 1 equals 175. So, 58 1/3 as an improper fraction is 175/3. Next, change 6 2/3 into an improper fraction. 6 times 3 equals 18, plus 2 equals 20. So, it's 20/3. So, here are your two fractions:
175/3 & 20/3
To divide fractions, I like to use a method called Keep Change Flip. Basically, you keep the first fractions the same, then change the sign. The division sign changes into a multiplication symbol. Now, your equation should look like this: 175/3 x 20/3. Next, flip the fraction from 20/3 into 3/20. This is what your equation should look like now: 175/3 x 3/20. Now you can multiply the fractions together. Before you do so, you can cross reduce to make it easier. What is a number that both 3 and 3 can be divided by? The correct answer is 3. 3/3= 1, so the equation is now 175/1 x 1/20. However, you can continue to cross reduce. You can also divide 175 and 20 by 5, so the equation changes into this: 35/1 x 1/20. Multiply numerator by numerator, denominator by denominator. So, the answer is 35/4, or 8 3/4 as a mixed number. Hope this helped!
Answer: B
Step-by-step explanation:
Using 6 decimals for pi = 3.141592


Using the z-distribution, it is found that she should take a sample of 46 students.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:

The margin of error is:

In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
Scores on the math portion of the SAT are believed to be normally distributed and range from 200 to 800, hence, by the Empirical Rule the standard deviation is found as follows:



The sample size is n when M = 29, hence:





n = 45.67.
Rounding up, a sample of 46 students should be taken.
More can be learned about the z-distribution at brainly.com/question/25890103
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