Answer:
Option 2 is the correct answer
Step-by-step explanation:
A quadratic function is a function in which the highest power to which the variable is raised is 2
1) f(x) = −8x3 − 16x2 − 4x
The given function is a cubic function because the highest power
to which the variable,x is raised is 3
2) f(x) = 3x²/4 + 2x - 5
The given function is a quadratic function because the highest power
to which the variable,x is raised is 2
3) f(x) = 4/x² - 2/x + 1
It can be rewritten as
f(x) = 4x^-2 - 2x^-1 + 1
The given function is not a quadratic function because the highest power to which the variable,x is raised is - 2
4) f(x) = 0x2 − 9x + 7
It can be rewritten as
f(x) = - 9x + 7
The given function is not a quadratic function because the highest power to which the variable,x is raised is 1
Answer:
3^7 * 3^(-4) = 3^(7 - 4) = 3^3 = 27
Answer:
0.430625=0.431
Step-by-step explanation:
Answer:
0.430625 = 0.431
Step-by-step explanation:
Let W represent winning, D represent a draw and L represent a loss.
12+ points can be garnered in each of the following ways.
6W 0D 0L
5W 1D 0L
5W 0D 1L
4W 2D 0L
4W 1D 1L
4W 0D 2L
3W 3D 0L
The probability of getting 12+ points is the sum of all these 7 probabilities.
Knowing that P(W) = 0.5
P(D) = 0.1
P(L) = 0.4
P(6W 0D 0L) = [6!/(6!0!0!)] 0.5⁶ 0.1⁰ 0.4⁰ = 0.015625
P(5W 1D 0L) = [6!/(5!1!0!)] 0.5⁵ 0.1¹ 0.4⁰ = 0.01875
P(5W 0D 1L) = [6!/(5!0!1!)] 0.5⁵ 0.1⁰ 0.4¹ = 0.075
P(4W 2D 0L) = [6!/(4!2!0!)] 0.5⁴ 0.1² 0.4⁰ = 0.09375
P(4W 1D 1L) = [6!/(4!1!1!)] 0.5⁴ 0.1¹ 0.4¹ = 0.075
P(4W 0D 2L) = [6!/(4!0!2!)] 0.5⁴ 0.1⁰ 0.4² = 0.15
P(3W 3D 0L) = [6!/(3!3!0!)] 0.5³ 0.1³ 0.4⁰ = 0.0025
The probability of getting 12+ points = 0.015625 + 0.01875 + 0.075 + 0.09375 + 0.075 + 0.15 + 0.0025 = 0.430625
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Answer: 1 out of 6
Step-by-step explanation: A number cube has 6 numbers on it. Only one of them is a two. If she were using two number cubes then she would have 2 out of 12 chances of landing on a number 2.
The <em><u>correct answer</u></em> is:
bx + 3y > 6 and y > 2x + 4
Explanation:
Looking at the second inequality, the y-intercept is 4 and the slope is 2. This means the graph of the line crosses the y-axis at (0, 4) and the line goes up 2 and over 1. Since it is greater than, this means the graph is shaded above it. Comparing this to the graph, the line for the blue part crosses the y-axis at (0, 4) and goes up 2 and over 1. The graph is also shaded above the line.
For the first inequality, bx+3y > 6, we want to isolate y. To do this, we subtract bx from each side:
bx+3y-bx > 6-bx
3y > 6-bx
Divide both sides by 3:
3y/3 > 6/3 - bx/3
y > 2 - (b/3)x
This means the line for this will have a y-intercept of 2 and decrease 1 while going over 3. The orange section does this. Additionally, since it is greater than, the graph should be shaded above the line. This one is, so this is the correct answer.