An ambulance has a mass of 5.44×10^5 ounces.

Mathematics

1 answer:

earnstyle [38]2 years ago

8 0

C.tons
544000 ounces converts to 17 tons.

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Let f(x)=3x+5 and g(x)=x^2 find (f-g)(x)

dlinn [17]

Answer:

(f - g)(x) = -x² + 3x + 5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

<u>Algebra I</u>

Function Notation
Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 3x + 5

g(x) = x²

(f - g)(x) is f(x) - g(x)

Substitute: (f - g)(x) = 3x + 5 - x²
Rewrite: (f - g)(x) = -x² + 3x + 5

7 0

2 years ago

I need help asap!!!

valentina_108 [34]

The answer is (7,6)

This is because a midpoint is in the exact middle, meaning that both sides are an equal distance away. You can find this by fining the difference between the two corresponding coordinates then adding that difference to the midpoint and that will give you your other endpoint.

Hope this helped !!

7 0

2 years ago

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$