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maxonik [38]
4 years ago
15

Simplify the expression (1/x^2 + 2/y)/(5/x - 6/y^2)

Mathematics
1 answer:
ozzi4 years ago
7 0

Answer:

y(y+2x^2)/x(5y^2-6x)

Step-by-step explanation:

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The table below shows all of the possible outcomes for rolling two six-sided number cubes.
Mice21 [21]

C. 1/4

There is a table with 36 possible outcomes. 9 of them are desired outcomes because they have an even number rolled first and then an odd number rolled second (a few random examples from the table would be 2,1, 2,3, 4,1, 4,5, 6,3 etc.)

All we have to do is make a fraction of the desired outcomes over the total number of possible outcomes. 9/36. That can be simplified into 1/4 and <em>voilà</em>, there is your answer.

Hope this helped ッ

3 0
3 years ago
Read 2 more answers
You are applying for graduate school at University A. In the past 42% of the applicants to this university have been accepted. I
Arisa [49]
The answer is A7 or A14 because the are the same
5 0
3 years ago
Match each series with the equivalent series written in sigma notation
PIT_PIT [208]

Answer:

3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n

2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

3 + 12 + 48 + 192 + 768

The expression can be written as:

3 \to 3*4^{0 --- 0

12 \to 3 * 4^{1 ---- 1

48 \to 3 * 4^{2 --- 2

192 \to 3 * 4^{3 ---- 3

768 \to 3 * 4^{4 ---- 4

For the nth term, the expression is:

Term = 3 * 4^{n ---- n

So, the summation is:

3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

Solving (b):

4 + 32 + 256 + 2048 + 16384

The expression can be written as:

4 \to 4 * 8^0 --- 0

32 \to 4 * 8^1 ---- 1

256 \to 4 * 8^2 --- 2

2048 \to 4 * 8^3 ---- 3

16384 \to 4 * 8^4 ---- 4

For the nth term, the expression is:

Term \to 4 * 8^n ---- n

So, the summation is:

4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n

Solving (c):

2 + 6 + 18 + 54 + 162

The expression can be written as:

2 \to 2 * 3^0 --- 0

6 \to 2 * 3^1 ---- 1

18 \to 2 * 3^2 --- 2

54 \to 2 * 3^3 ---- 3

162 \to 2 * 3^4 ---- 4

For the nth term, the expression is:

Term \to 2 * 3^n ---- n

So, the summation is:

2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n

Solving (d):

3 + 15 + 75 + 375 + 1875

The expression can be written as:

3 \to 3 * 5^0 --- 0

15 \to 3 * 5^1 ---- 1

75 \to 3 * 5^2 --- 2

375 \to 3 * 5^3 ---- 3

1875 \to 3 * 5^4 ---- 4

For the nth term, the expression is:

Term \to 3 * 5^n ---- n

So, the summation is:

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

5 0
3 years ago
Write a recursive rule and explicit rule for the arithmetic sequence 19,9,-1,-11, ...
serg [7]
★ Arithmetic Progression [ Explicit and Recursive notation ] ★

Arithmetic Sequence - 19 , 9 , -1 ...

Recursive Notation -

First term = 19
Common difference = -10

In subscript notation - [ a₁ = 19 , aₙ = aₙ-₁ -10 ]
In functional notation - f(n) = f (n -1) -10

Explicit Notation - f ( n ) = f ( 1 ) + d ( n - 1 )

= 19 - 10 ( n -1 )
= 29 - 10n

It's functional and subscript notations resides the same


6 0
3 years ago
Find the indicated sum for each sequence. S9 of –9, 36, –144, 576, ...
gogolik [260]

This is a geometric sequence with a common ratio of -4:

-9*-4=36

36*-4=-144

-144*-4=576

Thus, the 9th term would be equal to:

(-4)^5*576 which is -589824

The exponent 5 comes from the fact that 4 terms have already been displayed and we need 9-4 more terms to get to the 9th term. Since we are multiplying by -4 only, the 5 remains an exponent

5 0
4 years ago
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