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german
3 years ago
7

Which function is equivalent to h(x) = 10x?+ 9x - 1?

Mathematics
1 answer:
Elis [28]3 years ago
4 0

Answer:

i think it's this Bh(x) = (x + 1)(10x - 1)

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3 2/3 = 2 + N/3 solve for N
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If the question is 3*2/3=2+N/3
N=0

If the question is 2/3=2+N/3
N=-4
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Which is larger 143.0 millimeters or 143.0 decimeters?
Natali5045456 [20]
1 <span>millimeter = 10⁻³ m
1 </span><span>decimeter = 10⁻¹ m
So,</span>decimeters are larger units, and 143.0 decimeters > <span>143.0 millimeters .</span>
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Danessa needs to compare the area of one large circle with a diameter of 8 to the total area of 2 smaller circles with a diamete
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Answer:

The answer is: 1, 2, and 6

Step-by-step explanation:

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3 years ago
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A rancher wants to fence in an area of 1000000 square feet in a rectangular field and then divide it in half with a fence down t
frosja888 [35]

The shortest length of the fence used by the rancher in a rectangular field of 1000000 square feet is 4899 ft.

<h3>What is the area of a rectangle?</h3>

The area of a rectangle is a region enclosed in four corners where two opposite sides are equal. The area of the rectangle is mathematically expressed as:

Area of a rectangle = length(x) × breath(y)

1000000 sq.ft = (x) × (y) ---- (1)

However, to determine the fencing, we have:

Length of fencing = 2x + 2y  

  • since the rectangle has four sides and opposite sides are equal

Suppose we use the x-direction to estimate the region where the fencing is located, we have:

Length of fencing = 2x + 2y + x

Length of fencing = 3x + 2y ---- (2)

From equation (1), make (y) the subject of the formula and replace the value of y with equation (2)

The Length of fencing is:

\mathbf{L = 3x - 2( \dfrac{1000000}{x})}

\mathbf{\dfrac{dL}{dx} = 3 - \dfrac{2000000}{x^2} = 0}

\mathbf{ x^2= \dfrac{2000000}{3} }

\mathbf{ x= \dfrac{1000\sqrt{2}}{\sqrt{3}} }

\mathbf{x = \dfrac{1000 \sqrt{6}}{3}}

Now, if we replace the value with equation (1), then y will be:

\mathbf{y = \dfrac{1000000}{\dfrac{1000 \sqrt{6}}{3}} }\\ \\  \\ \\ \mathbf{y = \dfrac{3000 }{\sqrt{6}}}

\mathbf{x =500\sqrt{6}}

Now, the shortest length of the fencing can be computed by using the equation (2):

L = 3x + 2y

\mathbf{L = 3( \dfrac{1000  \sqrt{6}}{3}) + 2(500 \sqrt{6})}

\mathbf{L =1000  \sqrt{6} + 1000 \sqrt{6}}

\mathbf{L =2000  \sqrt{6} }

\mathbf{L \simeq 4899 \ ft}

Learn more about the area of a rectangle here:

brainly.com/question/25292087

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Which of the following phases are expressions
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Attach a picture of the question please.
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