1.58 hours or about an hour and a half. hope this helps :)
Answer:
(3,2)
Step-by-step explanation:
If you graph the equations, they cross at this point.
The question is not well formatted. A ell formatted version of the question type is attached and solved below :
Answer:
10
Step-by-step explanation:
Using trigonometry :
Taking the angle 45°
From trigonometry :
Sin θ = opposite / hypotenus
Opposite = s ; hypotenus = 10√2
Sin 45 = s / 10√2
Recall :
Sin 45 = 1/√2
We have ;
1/√2 = s / 10√2
s = 10√2 * 1/√2
s = 10√2 / √2
s = 10
Answer:
The equation of the line would be y = 4/9x
Step-by-step explanation:
In order to find the equation, we first need to find the slope. We can do this by using the slope equation with the points.
m(slope) = (y2 - y1)/(x2 - x1)
m = (9 - 0)/(4 - 0)
m = 9/4
Now that we have this, we can use point-slope form along with one of the points to get the equation.
y - y1 = m(x -x1)
y - 0 = 4/9(x - 0)
y = 4/9x
Answer:
[ See the attached picture ]
The diagonals of a parallelogram bisect each other.
✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.
✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.
Proof :
♕ And we're done! Hurrayyy! ;)
# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P
☄ Hope I helped! ♡
☃ Let me know if you have any questions! ♪
☂
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