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bixtya [17]
3 years ago
10

An investment offers $6,700 per year for 15 years, with the first payment occurring one year from now. a. If the required return

is 6 percent, what is the value of the investment today? (Do not round intermediate calculations and round your answer to 2 decimal places, e.g., 32.16.) Present value $ b. What would the value today be if the payments occurred for 40 years? (Do not round intermediate calculations and round your answer to 2 decimal places, e.g., 32.16.) Present value $ c. What would the value today be if the payments occurred for 75 years? (Do not round intermediate calculations and round your answer to 2 decimal places, e.g., 32.16.) Present value $ d. What would the value today be if the payments occurred forever? (Do not round intermediate calculations and round your answer to 2 decimal places, e.g., 32.16.) Present value $
Business
1 answer:
maksim [4K]3 years ago
8 0

Answer:

a.$65,072.07

b.$100,810.19

c.$110,254.18

d.$111,666.67

Explanation:

a. The value of investment today if payment per year of $6,700 is made for 15 years is given as follows:

Present value today=R[(1-(1+i)^-n)/i]

Where

R=payment to made yearly=$6,700

i=interest per annum=6%

n=number of payments=15

Present value today=6,700[(1-(1+6%)^-15)/6%]=$65,072.07

b. The value of investment today if payment per year of $6,700 is made for  40 years is given as follows:

Present value today=6,700[(1-(1+6%)^-40)/6%]=$100,810.19

c. The value of investment today if payment per year of $6,700 is made for 75 year is given as follows:

Present value today=6,700[(1-(1+6%)^-75)/6%]=$110,254.18

d. The value of investment today if payment per year of $6,700 occurred forever

Present value today=P/i=6,700/6%=$111,666.67

where P=6,700, i=6%

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Depreciation by Two Methods
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The amount of annual depreciation by the straight-line method is $18,800.

<h3>Annual depreciation</h3>

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