It’s 57 57 57 okay i had this question once
        
             
        
        
        
The purpose of the grid is to help you record possible and impossible combinations. The repeat of the headings 1st, 2nd, 3rd, 4th helps you compare to both shirt color and name.
Each given statement has certain implications. You are expected to be able to determine as many of those as you can, and mark the grid accordingly.
The first statement says two girls slide down before two other girls. This means the first two girls listed cannot be 3rd or 4th in line, and the last two girls listed cannot be 1st or 2nd in line. It also means that none of the named girls is wearing the blue shirt (so Madeline must be wearing it). These implications are marked in the attachment with X and a circled 1, to indicate to you that the first statement was where we got the X. The X is used to signify an impossible combination.
The second statement tells you the purple shirt will not be 3rd or 4th in line, since at least two girls are after it. It tells you that Alexis is not wearing purple or yellow (so must be wearing white), and it tells you that Alexis and the yellow shirt are not first in line. (We alread knew that about Alexis.)
The third statement lets you finish the problem. We just found that Alexis is wearing the white shirt, so it tells you Madeline is 2nd in line and Alexis is 3rd. (Alexis is 3rd or 4th, but so is Lauren. The only way Madeline can be next to Alexis is for Madeline to be 2nd and Alexis 3rd.) The check marks labeled with a circled 3 are the conclusions we drew from statement 3.
Since the yellow shirt is not first, Lauren must be wearing it 4th in line.
The final conclusion is ...
- Hanna, purple
- Madeline, blue
- Alexis, white
- Lauren, yellow
Once you have identified a combination, it can help to mark off the others in that row and column (of the group of 4 rows and columns) as being impossible. This can narrow the choices for the others. I didn't do that here because it makes the diagram busier and the sequence of marks less clear.
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It is a good idea to check your final answer with the original problem statements to make sure the answer is consistent with them.
 
        
             
        
        
        
Answer:
24/35
Step-by-step explanation:
There is a website called calculator soup that will help you with any other problems as well. It doesnt just tell you the answer but shows work as well. :)
 
        
             
        
        
        
Given that R(ABCDE) is in Boyce-Codd normal form.
And AB is the only key for R.
Definition
A relational nontrivial Schema R is in BCNF if FD (X-A) holds in R, Super key of R. whenever then X is
a
Given that AB is the only key for R.
ABC E (Yes).
check if ABC is a Super key. AB is a key, ABC is A B C E is in BONE a super key.
2) ACE B
(NO). no Check if ACE As there is ACE is not a Super key? AB in Super key. ACE.
ACE B
is
Boyce-Codd Normal Form not in BENE (NO)
3) ACDE → B           (NO)
check if is a super key. ACDE
As ACDE there is not any AB Tn ACDE. a super key.
ACDEB is not in BCNF.
4) BS → C → (NO)
As there is no AB in BC ~. B(→ not in BCNF
BC is not a super key.
5) ABDE (Yes).
Since AB is a key.
ABO TS a super key.
.. ABDE → E is in BCNF
Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AB is the only key for R, identify each of these FDs from the following list. Answer Yes or No and explain your answer to receive points.
1. ABC E
2. ACE B
3. ACDE B
4. BC C
5. ABD E
Learn more about Boyce-Codd Normal Form at
brainly.com/question/14299832
#SPJ4
 
        
             
        
        
        
Answer:
37
Step-by-step explanation:
To find the average, you need to add all the numbers in the set and divide that value by the total amount of numbers there are,
We already know that the average of the set of temperatures is 40,
Since there are 5 different days with temperatures, multiply 40 by 5,
40 × 5
= 200
200 is what all the temperatures should equal once they are added up,
Now add 40, 39, 44, and 40 together,
40 + 39 + 44 + 40
= 163
Now subtract 163 from 200,
200 - 163 
= 37
Therefore the temperature that was recorded on the fifth day was 37f.