Outside
length is 7 inches
Outside Width
is 5 inches.
SOLUTION
Length of outside edge = 7 inches
Scale Factor: 1in = 2.5ft
New length of outside edge = (7 * 2.5)ft
New length = 17.5ft
Width of outside edge = 5 inches
Scale Factor: 1in = 2.5ft
New width of outside edge = (5 * 2.5)ft
New Width = 12.5ft
Therefore, the new dimension of the outside edges of the
frame is 17.5ft by 12.5ft
Well ummm for example .9746 the 9 is in the tenths place the 7 is in the hundredths place the 4 is in the thousandths place the 6 is in the ten thousandths place
Answer:
Step-by-step explanation:
La primera ya que es .35 y .40 hay que igualar
Evaluate the function at the three values of the range and see what you get. The appropriate choice is ...
... D) {15, 3, 0}
_____
Evaluation can sometimes be simpler if you rearrange the function to a form called "Horner's form."
... f(x) = (x -4)x +3
Then the evaluation looks like (for x=-2) ...
... f(-2) = (-2-4)(-2)+3 = (-6)(-2) +3 = 12 +3 = 15
This is sufficient to identify D as the answer of choice.