P = 4d +dgt
dgt = P -4d
divide both sides by dt.
g = (P-4d)/dt
Answer:
f = 6y + 3
Step-by-step explanation:
<u>The equation to reflect this condition is:</u>
<u>Where</u>
- 3 - is constant, the initial number of flights
- 6 - coefficient, number of flights per year
- y- number of years
- f- total number of flights
Answer:
0.865
Step-by-step explanation:
To solve for the probability we would be using the formula:
F(x) = 1 - e^−λx
Therefore, P(x > 2000) = F(x) = 1 - e^−λx
Mean = 1000 hours
λ = 1/mean = 1/1000 hours
x= 2000 hours
F(x) = 1 - e^−(1/1000)2000
F(x) = 1 - e^−2
= 0.8646647168
Therefore, the probability the the circuit will last at least 2000 hours = 0.865
Answer:
3.64 × 10(raised to the power 7)
2.6 × 10⁴
Tha answer
s are 200 and there are 20 tens
