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kondor19780726 [428]
3 years ago
15

a video game arcade offers a yearly membership with reduced rates for game play. A single membership costs $60 per year. Game to

kens can be purchased by members at the reduced rate of $1.00 per 10 tokens. Which statements represent the function of the yearly cost in dollars, y, based on x, the number of game tokens purchased for a member of the arcade? Check all that apply. The slope of the function is $1.00. The y-intercept of the function is $60. The function can be represented by the equation y = x + 60. The domain is all real numbers. The range is {y| y ≥ 6
Mathematics
2 answers:
7nadin3 [17]3 years ago
6 0

slope is $0.10            <em>($1.00 per 10 tokens = $0.10)</em>

y-intercept is $60    <em>($60 is the annual fee)</em>

y = .10x + 60            <em>(y = mx + b)</em>  

domain is x ≥ 0        <em>(you can't buy a negative number of token)</em>

range is y ≥ 60        <em>(input the domain (x ≥ 0) to find the range)</em>

Answer: the y-intercept of the function is $60

Nonamiya [84]3 years ago
4 0

Answer:

the real answer is b, c, and e

Step-by-step explanation:

i just took the test

zizaboo06
2 years ago
thx
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The National Transportation Safety Board publishes statistics on the number of automobile crashes that people in various age gro
ra1l [238]

Answer:

a) Null hypothesis:p\leq 0.12  

Alternative hypothesis:p > 0.12  

b) z_{\alpha}=1.64

c) z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362  

d) p_v =P(z>1.362)=0.0866  

e) For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

Step-by-step explanation:

Information given

n=1000 represent the random sample selected

X=134 represent the number of young drivers ages 18 – 24 that had an accident

\hat p=\frac{134}{1000}=0.134 estimated proportion of young drivers ages 18 – 24 that had an accident

p_o=0.12 is the value that we want to verify

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v{/tex} represent the p valuePart aWe want to verify if the population proportion of young drivers, ages 18 – 24, having accidents is greater than 12%:  Null hypothesis:[tex]p\leq 0.12  

Alternative hypothesis:p > 0.12  

The statistic would be given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Part b

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.05 of the area in the right and we got:

z_{\alpha}=1.64

Part c

For this case the statistic would be given by:

z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362  

Part d

The p value can be calculated with the following probability:

p_v =P(z>1.362)=0.0866  

Part e

For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

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saul85 [17]
\frac{6}{15} = \frac{2}{c}   Multiply both sides by 15
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6c = 30   Divide both sides by 6
c = 5   
7 0
2 years ago
Sam bought 2 1/4 pounds of Swiss cheese and 1 1/2 pounds of cheddar at the deli. How many pounds of cheese did Sam buy altogethe
DerKrebs [107]
2 1/4 + 1 1/2 

2 + 1 = 3
1/4 + 1/2 = 1/4 + 2/4 = 3/4

so ur answer is 3 3/4 lbs of cheese in total
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Answer:

Answer is 3.3 simplfly is 3.3 have good day

Step-by-step explanation:

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