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Alex73 [517]
3 years ago
6

Shawna invests $5,048 in a savings account with a fixed annual interest rate of 4% compounded 12 times per year. How long will i

t take for the account balance to reach $6,163.59?
Mathematics
1 answer:
Elena-2011 [213]3 years ago
3 0

Answer:

5 years

Step-by-step explanation:

In the question we are given;

  • Amount invested or principal amount as $5048
  • Rate of interest as 4% compounded 12 times per year
  • Amount accrued as $6,163.59

We are required to determine the time taken for the money invested to accrue to the given amount;

Using compound interest formula;

A=P(1+\frac{r}{100})^n

where n is the interest period and r is the rate of interest, in this case, 4/12%(0.33%)

Therefore;

6,163.59=5,048(1+\frac{0.333}{100})^n

1.221=(1+\frac{0.333}{100})^n

1.221=(1.0033)^n

introducing logarithms on both sides;

log1.221=log(1.0033)^n\\n=\frac{log1.221}{log1.0033} \\n=60.61

But, 1 year = 12 interest periods

Therefore;

Number of years = 60.61 ÷ 12

                            = 5.0508

                            = 5 years

Therefore, it will take 5 years for the invested amount to accrue to $6163.59

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From a point A that is 8.20 m above level ground, the angle of elevation of the top of a building s 31 deg 20 min and the angle
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Answer:

30.11 meters ( approx )

Step-by-step explanation:

Let x be the distance of a point P ( lies on the building ) from the top of the building such that AP is perpendicular to the building and y be the distance of the building from point A, ( shown in the below diagram )

Given,

Point A is 8.20 m above level ground,

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Now, 1 degree = 60 minutes,

⇒ 1\text{ minute } =\frac{1}{60}\text{ degree }

20\text{ minutes }=\frac{20}{60}=\frac{1}{3}\text{ degree}

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By the below diagram,

tan ( 12^{\circ} 50') = \frac{8.20}{y}

tan(12+\frac{5}{6})^{\circ}=\frac{8.20}{y}

tan (\frac{77}{6})^{\circ}=\frac{8.20}{y}

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Now, again by the below diagram,

tan (31^{\circ}20')=\frac{x}{y}

tan(31+\frac{1}{3})=\frac{x}{y}

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Answer:

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Rewritten steps: 2x-3y=12 then move constant to the left by adding its opposite to both sides which gives you 2x-3y-12=12-12. After the sum of two opposites equals 0 which is 2x-3y-12=0

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Answer:

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