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nignag [31]
3 years ago
9

How do u write 4408730 in expanded form?

Mathematics
1 answer:
STALIN [3.7K]3 years ago
5 0
Do you need the expanded notation form, or expanded factor form?
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Two hundred fifty people were surveyed to determine their favorite mode of transportation. What number of people chose walking?
4vir4ik [10]

Answer:

14

Step-by-step explanation:

6 0
3 years ago
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Find the domain of <br> f(x) = - squareroot x^2 - 4
erma4kov [3.2K]

Answer:

d. x ≥ 2 or x ≤ -2

Step-by-step explanation:

The domain is the set of all possible x-values that will make the function work.

For the function to work, the radicand cannot be negative.

x² - 4 ≥ 0

x² ≥ 4

x ≥ 2    -x ≥ 2

            x ≤ -2

The domain is x ≥ 2 and x ≤ -2.

The graph of your function shows that ƒ(x) does not exist when -2 < x < 2.

6 0
2 years ago
Find the distance between A and B.
Bond [772]

Answer: A

Step-by-step explanation: you have to use the 2 points distance formula that is ✓(xb - xa)^2 + (yb - ya)^2 so ✓(6+6)^2 + (-3-4)^2 = ✓144 + 49 = ✓193

6 0
2 years ago
Suppose x follows a continuous uniform distribution from 1 to 5. determine the conditional probability p(x &gt;2.5 | x ≤ 4).
Rainbow [258]
Because the random variable x follows a continuous uniform distribution from x=1 to x=5, therefore
p(x) = 1/4,  x=[1, 5]
The value of p(x) ensures that the total area under the curve = 1.

The conditional probability p(x > 2.5 | x ≤ 4) is the shaded portion of the curve. Its value is
p(x > 2.5 | x ≤4) = (1/4)*(4 - 2.5) = 0.375

Answer: 0.375

8 0
3 years ago
A high school teacher teaches three classes per day. Her first class has double the number of students as her
Aneli [31]

Answer: 15 students in her second class.

Step-by-step explanation:

Let A, B, and C stand for the number of students in each class. See the attached table.

The column labelled "Students" is formed by assinging B to the second class and finding how the other two classes relate to B. Class A has twice as many students as class B, so A = 2B. Class C has 5 more students than B, so C = B+5.

The total students amount to 65, whcih is the sum of A, B, and C:

A + B + C = 65

Substitute the values of A and C into this equation:

A + B + C = 65

2B + B + (B+5) = 65

4B + 5 = 65

4B = 60

B = 16

Use B=16 and solve for the other two classes (dotted blue line).

3 0
2 years ago
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