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nignag [31]
3 years ago
9

How do u write 4408730 in expanded form?

Mathematics
1 answer:
STALIN [3.7K]3 years ago
5 0
Do you need the expanded notation form, or expanded factor form?
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For each table, determine whether it shows that x and y are proportional.
myrzilka [38]

9514 1404 393

Answer:

  1. proportional, 6

  2. not proportional

Step-by-step explanation:

<u>Table 1</u>

Each y-value is 6 times the corresponding x-value, so the variables are proportional, and y = 6 times x.

<u>Table 2</u>

The ratios of y to x are 2, 4, 8, so are not the same. The values are not proportional.

8 0
3 years ago
The formula for the area of a trapezoid is A = {h(bi + b2), where h is the height
Rina8888 [55]

Answer:h = 2((A)/(b1+b2))

Step-by-step explanation:

7 0
3 years ago
I need help with this
WITCHER [35]

Answer:

8.1

Step-by-step explanation:

8.1 is the highest as you would look at the first number before the decimal and is the highest in this equation.

3 0
3 years ago
Read 2 more answers
Solve the rational equation 1/n-4 - 2/n = 3/4-n
Leokris [45]

Answer:

n=4

Step-by-step explanation:

Given equation: \[\frac{1}{n-4}-\frac{2}{n}=\frac{3}{4-n}\]

Simplifying the Left Hand Side of the equation by taking the LCM of the denominator terms:

\[\frac{n}{n*(n-4)}-\frac{2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2n + 8}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{8 - n}{n*(n-4)}=\frac{3}{4-n}\]

=> \[(8-n)*(4-n) =n*(n-4)*3\]

=> \[n-8 =3n\]

=> \[2n =8\]

=> n = 4

5 0
3 years ago
What is true about the sum of the two polynomials?<br> 6s^2t – 2st^2<br> 4s^2t – 3st^2
Snowcat [4.5K]
The sum is 10s^2t-5st^2. With two separate sections it’s a binomial, and the sum of the powers of the variables is 2+1=3, it has a degree of 3.
7 0
3 years ago
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