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qaws [65]
3 years ago
7

Pls need help now. ​

Mathematics
1 answer:
tangare [24]3 years ago
5 0

Answer:

  θ = {π/6, 5π/6} +2kπ . . . . for any integer k

Step-by-step explanation:

Multiplying by the product of the denominators, we can simplify this to ...

  sin(θ)² +(1+cos(θ))² = 4sin(θ)(1+cos(θ))

  sin(θ)² +1 +2cos(θ) +cos(θ)² = 4sin(θ)+4sin(θ)cos(θ)

  2 +2cos(θ) = 2sin(θ)(2 +2cos(θ)) . . . . show similar factors

  2(2sin(θ) -1)(1 +cos(θ)) = 0 . . . . subtract left side, complete the factoring

These factors are zero when ...

  2sin(θ) -1 = 0   ⇒   sin(θ) = 1/2   ⇒   θ = π/6, 5π/6

  1 +cos(θ) = 0 . . . . . extraneous solution; makes equation undefined

__

Solutions are periodic with period 2π, so the complete solution set is ...

 θ = {π/6, 5π/6} +2kπ . . . . for any integer k

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Cx =d+r solve for x .! pls explain
elena-14-01-66 [18.8K]

Answer: x=\frac{d+r}{c}

Step-by-step explanation:

Simply divide by c to isolate x.

\frac{cx}{c}=\frac{d+r}{c}

x=\frac{d+r}{c}

5 0
4 years ago
In a sample of 234 individuals over the age of 25, chosen at random from the state of Oregon, 48 did not have a high school dipl
Anna71 [15]

Answer:

The upper bound of a 95% confidence interval for the proportion of individuals over the age of 25 in Oregon who do not have a high school diploma is of 0.2568.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

In a sample of 234 individuals over the age of 25, chosen at random from the state of Oregon, 48 did not have a high school diploma.

This means that n = 234, \pi = \frac{48}{234} = 0.2051

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2051 + 1.96\sqrt{\frac{0.2051*0.7949}{234}} = 0.2568

The upper bound of a 95% confidence interval for the proportion of individuals over the age of 25 in Oregon who do not have a high school diploma is of 0.2568.

6 0
3 years ago
What is 9 divided by 2 over 7?
andreev551 [17]
2 over 7 =0,28
9/0,28=32,14

Hope it helped
6 0
3 years ago
Please Help Me! "Given ABC ~ ADE with AB = 2 Centimeters, and DE= 10 Centimeters" Whats the length of BC?
Nataliya [291]
C. 4 Centimeters is the answer
6 0
4 years ago
Divide <br><br> (3x^2 + 9x + 7) divide by (x+2)
scZoUnD [109]

Answer:

The remainder is: 3x+3

The quotient is: 1

Step-by-step explanation:

We need to divide

(3x^2 + 9x + 7) by (x+2)

The remainder is: 3x+3

The quotient is: 1

The solution is attached in the figure below.

3 0
3 years ago
Read 2 more answers
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