Question

Divide (3x^2 + 9x + 7) divide by (x+2)

Answer 1

Answer:

$3x+3+\frac{1}{x+2}$

Step-by-step explanation:

We are to divide the polynomial $3x^2 + 9x + 7$ by $x+2$.

For that, we will first divide the leading coefficient of the numerator $\frac{3x^2}{x}$ by the divisor.

So we get the quotient: $3x$ and will multiply the divisor $x+2$ by $3x$ to get $3x^2+6x$.

Next, we will subtract $3x^2+6x$ from $3x^2 + 9x + 7$ to get the remainder $3x+7$.

Therefore, we get $3x+\frac{3x+7}{x+2}$.

Now again, dividing the leading coefficient of the numerator by the divisor $\frac{3x}{x}$ to get quotient $3$.

Then we will multiply $x+2$ by $3$ to get $3x+6$.

Then, we will subtract $3x+6$ from $3x+7$ to get the new remainder $1$.

Therefore, $\frac{3x^2 + 9x + 7}{x+2}=3x+3+\frac{1}{x+2}$

Answer 2

Answer:

The remainder is: 3x+3

The quotient is: 1

Step-by-step explanation:

We need to divide

(3x^2 + 9x + 7) by (x+2)

The remainder is: 3x+3

The quotient is: 1

The solution is attached in the figure below.