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miss Akunina [59]
2 years ago
9

Divide (3x^2 + 9x + 7) divide by (x+2)

Mathematics
2 answers:
ludmilkaskok [199]2 years ago
5 0

<u>Answer:</u>

3x+3+\frac{1}{x+2}

<u>Step-by-step explanation:</u>

We are to divide the polynomial 3x^2 + 9x + 7 by x+2.

For that, we will first divide the leading coefficient of the numerator \frac{3x^2}{x} by the divisor.

So we get the quotient: 3x and will multiply the divisor x+2 by 3x to get 3x^2+6x.

Next, we will subtract 3x^2+6x from 3x^2 + 9x + 7 to get the remainder 3x+7.

Therefore, we get 3x+\frac{3x+7}{x+2}.

Now again, dividing the leading coefficient of the numerator by the divisor \frac{3x}{x} to get quotient 3.

Then we will multiply x+2 by 3 to get 3x+6.

Then, we will subtract 3x+6 from 3x+7 to get the new remainder 1.

Therefore, \frac{3x^2 + 9x + 7}{x+2}=3x+3+\frac{1}{x+2}

scZoUnD [109]2 years ago
3 0

Answer:

The remainder is: 3x+3

The quotient is: 1

Step-by-step explanation:

We need to divide

(3x^2 + 9x + 7) by (x+2)

The remainder is: 3x+3

The quotient is: 1

The solution is attached in the figure below.

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Fifteen years ago, you deposited $12,500 into an investment fund. Five years ago, you added an
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Answer:

a) 8.16%

b) $65,762.50

c) $39,701.07

Step-by-step explanation:

Given:

15 years ago, Initial investment = $12500

5 years ago, Investment = $20000

Nominal interest = 8% semi annually for first 10 years

Interest2= 6.5% compunded annually for last five years

a) for the effective annual interest rate (EAR) in the first 10 years, let's use the formula:

[1+(nominal interest rate/number of compounding periods)]^ number of compounding periods-1

EAR = [1 + (\frac{0.08}{2})]^2 - 1

= (1 + 0.04)^2 - 1

= (1.04)^2 - 1

= 1.0816 - 1

= 0.0816

= 8.16%

The effective annual interesting rate, EAR = 8.16 %

b) To find the amount in my account today.

Let's first find the amount for $12500 for 10 years compounded semi annually

= 12,500 +( 12,500 * 8.160% * 10)

= $ 22,700

Let's also find the amount for $32,500($12,500+$20,000) for 5 Years compoundeed annually

$32,500 + ($32,500 * 6.5% *5)

= $ 43,062.50

Money in account today will be:

$22,700 + $43,062.50

= $65,762.50

c) Let's the amount I should have invested to be X

For first 10 years at 8.160%, we have:

Interest Amount = ( X * 8.160% * 10 ) = 0.8160 X

For next 5 years at 6.5%, we have:

Interest Amount = (X * 6.5% * 5) = 0.325 X

Therefore the total money at the end of 15 Years = 85000

0.8160X + 0.3250X + X = $85,000

= 2.141X = $85,000

X = 85,000/2.141

X = 39,701.074 ≈ $39,700

If I wish to have $85,000 now, I should have invested $39,700 15 years ago

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Answer:

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Step-by-step explanation:

because :

2/10 equals to 10/2 So 6/10 ÷ 2/10 =6/10×10/2

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Step-by-step explanation:

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