What percent is the change in the price if: The price was $160 and now it is $40?

<img src="https://tex.z-dn.net/?f=8%20-%20%20%7B2%7D%5E%7B2%7D%20%20%2B%203%20-%205" id="TexFormula1" title="8 - {2}^{2} + 3 -

Vlad1618 [11]

The answer should be 8+[(2^2)+3]-5

Hope this helps!

3 0

3 years ago

Cindy and Zoey work at a store. Both girls earn $6.25 per hour

wolverine [178]

Answer:

Step-by-step explanation:

I think this is your full question, right?

<em>Cindy and Zoey work at a store. Both girls earn $6.25 per hour. During a normal week Cindy works 15 hours and Zoey works 20 hours. The expression 6.25(15) + 6.25(20) can be used to calculate the total amount of money that the girls earned in one week. Which expression shows another way to calculate the amount of money the girls earn in one week? </em>

My answer:

The expression shows another way must be equal to: <em>6.25(15) + 6.25(20) </em>

<=> 6.25 (15+20)

Because both girls earn the same per hour.

8 0

3 years ago

How to solve for axis of symmetry for y=(x+2)(x-4)

lianna [129]

Answer:

x = 1

Step-by-step explanation:

you can first find the two zeroes

that would be

x + 2 = 0

x - 4 = 0

x = {-2, 4}

then you average them

-2 + 4 = 2

2 / 2 = 1

the aos is 1

5 0

2 years ago

Read 2 more answers

How do you simplify this

katen-ka-za [31]

It's 2/5 in decimal form it is 0.4.

5 0

3 years ago

Graph and label the image of the figure below after a dilation by a factor of 1/2.

neonofarm [45]

Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

$\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\ \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\ \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}$ $\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\ \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}$

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

3 0

11 months ago